Answer:
Step-by-step explanation:
Given that a teacher gives a test to a large group of students. The results are closely approximated by a normal curve
mu =74 and sigma =8
A grade starts from 100-8 = 92nd percentile
Z score for 92nd percentile = 1.405
X score = 74+8(1.405) = 85.24
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B cut off is to next 16%
Hence C would start for scores below 100-(8+16) = 76%
76th percentile = 0.705*8+74 =79.64
Answer:
The coordinates of B is (3, - 5)
Step-by-step explanation:
A(6, 1)
C(2, -7)
Coordinates of point B such that AB = 1/3 × BC
Hence we have;

Therefore BC = 3/4 × AC
Hence, AB = 1/3 × BC = 1/3 × 3/4 × AC = 1/4 × AC
AC = √((6 - 2)² + (1 - (-7))²) = √(16 + 64) = √80 = 4·√5
AB = 1/4 × 4·√5 = √5
Therefore;
AB² = (x - 6)² + (y - 1)² = 5
Slope = (1 - (-7))/(6 - 2) = 2
Hence the y coordinate of B = -7 + sin(tan⁻¹(2)) ×√5 = -5
The x coordinate of B = 2 + cos(tan⁻¹(2)) ×√5 = 3
The coordinates of B = (3, - 5)
The first term is x^4.
The second term is 8x^3
Hi there!
We are looking for perpendicular angles, which means the angle between the streets is 90 degrees. So, each time we need to find the street that intersects the given street with a 90 degree angle.
On this map, Oxford Street is perpendicular to Waterloo St., and Rosewood Street is perpendicular to Oak St..
The answers are (in correct order): Waterloo St. and Oak St..
~ Hope this helps you!