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Ber [7]
2 years ago
14

(04.07) Two separate bacteria populations grow each month and are represented by the functions f(x) = 3x and g(x) = 7x + 6. In w

hat month is the f(x) population greater than the g(x) population? (2 points)
Mathematics
2 answers:
fenix001 [56]2 years ago
7 0

Answer: Hello there!

Here we have two functions:

f(x) = 3x

g(x) = 7x + 6

We want to see in what month f(x) is bigger than g(x)

or

f(x) > g(x)

3x > 7x + 6

we can subtract 7x in both sides:

3x  - 7x > 7x + 6 - 7x

-4x > 6

Now, this means that x should be a negative number, this has no sense because if we are measuring if we put a negative number there, then we will end up with a negative number of population.

Then there is no month where f(x) is greater than g(x)

This also can be seen because g(x) has a positive intercept when g(x) has an intercept equal to zero, and because g(x) has a bigger slope, which means that grows faster than f(x) as the months passes.

Firlakuza [10]2 years ago
6 0

3x> 7x+6

subtract 7x from each side

-4x > 6

divide by -4  which causes the inequality sign to flip

x < -6/4

x < 2/3

The f(x) population stops being larger in the first month

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A manufacturer of paper coffee cups would like to estimate the proportion of cups that are defective (tears, broken seems, etc.)
Maksim231197 [3]

Answer:

a

  The 95% confidence interval is  0.0503  <   p < 0.1297

b

The sample proportion is  \r p =  0.09

c

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d

 The standard error is  SE   =0.020

Step-by-step explanation:

From the question we are told that

   The  sample size is  n =  200

     The number of defective is  k =  18

The null hypothesis is  H_o  :  p  =  0.08

The  alternative hypothesis is  H_a  :  p > 0.08

Generally the sample proportion is mathematically evaluated as

            \r p =  \frac{18}{200}

            \r p =  0.09

Given that the confidence level is  95% then the level  of significance is mathematically evaluated as

        \alpha  =  100 -  95

        \alpha  =  5\%

        \alpha  =  0.05

Next we obtain the critical value of  \frac{ \alpha }{2} from the normal distribution table, the value is  

        Z_{\frac{\alpha }{2} } =  1.96

Generally the standard of error is mathematically represented as

          SE   =  \sqrt{\frac{\r p (1 -  \r p)}{n} }

substituting values

         SE   =  \sqrt{\frac{0.09  (1 -  0.09)}{200} }

        SE   =0.020

The  margin of error is  

       E =  Z_{\frac{ \alpha }{2} }  * SE

=>    E =  1.96  *  0.020

=>   E =  0.0397

The  95% confidence interval is mathematically represented as

     \r p  -  E  <  \mu <  p <  \r p  + E

=>   0.09 - 0.0397  <  \mu <  p < 0.09 + 0.0397

=>  0.0503  <   p < 0.1297

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