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stellarik [79]
2 years ago
12

Consider this system of equations. Which shows the second equation written in slope-intercept form? y = 3 x minus 2. 10 (x + thr

ee-fifths) = 2 y y = 5 x + StartFraction 3 Over 10 EndFraction y = 5 x + 3 y = one-fifth x + StartFraction 3 Over 25 EndFraction y = one-half x + 6
Mathematics
2 answers:
Bas_tet [7]2 years ago
8 0

Answer:

The answer is B

Step-by-step explanation:

Can i have Brainliest

Arte-miy333 [17]2 years ago
7 0

Question

Consider this system of equations. Which shows the second equation written in slope-intercept form?

y = 3x - 2.

10(x + \frac{3}{5} ) = 2y

A. y = 5x + \frac{3}{10}

B. y = 5x + 3

C. y = \frac{1}{5} x + \frac{3}{25}

D. y = \frac{1}{2} x + 6

Answer:

B. y = 5x + 3

Step-by-step explanation:

Given

Equation 1: y = 3x - 2.

Equation 2: 10(x + \frac{3}{5} ) = 2y

Required:

Equivalent of equation 2

To get an equivalent of equation 2 (in slope intercept form), first we have to simplify equation 2

10(x + \frac{3}{5} ) = 2y

Open the bracket

10*x + 10 *\frac{3}{5} = 2y

10x + \frac{30}{5} = 2y

Simplify fraction

10x + 6 = 2y

Divide through by 2

\frac{10x}{2}  + \frac{6}{2} = \frac{2y}{2}

5x + 3 = y

Re-arrange

y = 5x + 3

The next step is to compare each of option A through D with y = 5x + 3

A.

y = 5x + \frac{3}{10} is not equal to y = 5x + 3

We check the next available option

B.

y = 5x + 3 is equal to y = 5x + 3

This option is equivalent to the second equation in slope-intercept form.

We check further if there are more equivalent options

C.

y = \frac{1}{5} x + \frac{3}{25}

Convert fraction to decimal

y = 0.2x + 0.12

This is not equal to y = 5x + 3

D.

y = \frac{1}{2} x + 6

Convert fraction to decimal

y = 0.5x + 6

This is not equal to y = 5x + 3

Hence, the only equation that is equivalent to the second equation written in slope intercept form is Option B

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Answer:

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kari74 [83]

Answer:

1131 pounds.

Step-by-step explanation:

We have been given that an unloaded truck and trailer, with the driver aboard, weighs 30,000 pounds. When fully loaded, the truck holds 26 pallets of cargo, and each of the 18 tires of the fully loaded semi-truck bears approximately 3,300 pounds.

First of all, we will find weight of 18 tires by multiplying 18 by 3,300 as:

\text{Weight of tires of the fully loaded semi-truck}=18\times 3,300

\text{Weight of tires of the fully loaded semi-truck}=59,400

The weight of 26 pallets would be weight of 18 tires minus weight of unloaded truck.

\text{Weight of 26 pallets of cargo}=59,400-30,000

\text{Weight of 26 pallets of cargo}=29,400

Now, we will divide 29,400 by 26 to find average weight of one pallet of cargo.

\text{Average weight of one pallet of cargo}=\frac{29,400}{26}

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3 0
2 years ago
PLEASE HELP ME!
algol13

Step-by-step explanation:

1.\sum_{i=1}^{5}3i

The simplest method is "brute force".  Calculate each term and add them up.

∑ = 3(1) + 3(2) + 3(3) + 3(4) + 3(5)

∑ = 3 + 6 + 9 + 12 + 15

∑ = 45

2.\sum_{k=1}^{4}(2k)^{2}

∑ = (2×1)² + (2×2)² + (2×3)² + (2×4)²

∑ = 4 + 16 + 36 + 64

∑ = 120

3.\sum_{k=3}^{6}(2k-10)

∑ = (2×3−10) + (2×4−10) + (2×5−10) + (2×6−10)

∑ = -4 + -2 + 0 + 2

∑ = -4

4. 1 + 1/4 + 1/16 + 1/64 + 1/256

This is a geometric sequence where the first term is 1 and the common ratio is 1/4.  The nth term is:

a = 1 (1/4)ⁿ⁻¹

So the series is:

\sum_{j=1}^{7}(\frac{1}{4})^{j-1}

5. -5 + -1 + 3 + 7 + 11

This is an arithmetic sequence where the first term is -5 and the common difference is 4.  The nth term is:

a = -5 + 4(n−1)

a = -5 + 4n − 4

a = 4n − 9

So the series is:

\sum_{j=1}^{5}(4j-9)

5 0
2 years ago
The function f(x)=tan(3/2x-pi/2) has:
zlopas [31]
I think the best option here is B. <span>period 2pi/3 and asymptote at x=0
</span>because period of tanx is pi so period of tan(3/2x) is pi/(3/2) = 2pi/3. I hope this can work good for you. 
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2 years ago
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Alex17521 [72]
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The reason for this is when you apply a vertical stretch, because it changes the y-values (which causes it to vertically stretch or appear skinnier when graphed), you would multiply 4 to f(x) which would look like 4x^2.

Then, since you have a reflection over the x-axis, you must multiply a -1 to f(x) to reflect it over the x-axis which would result in -4x^2.

Finally, it also asks to shift the graph right 3 which by moving it right, you change the x values meaning you will perform f(x-3) to achieve this (subtract the value from x when you move right, and add the value to x when you move left).

This therefore results in your answer, the new graph would be
g(x)= -4(x-3)^2 or choice B.
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2 years ago
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