Answer:
1) 2/7
2) 8/11
3) 3/2 or 1 1/2
4) 32/35
Step-by-step explanation:
1.5/7•14/35
= 5/7 × 14/35
Using Cancellation method
= 1/1 × 2/7
= 2/7
2.[4/5][10/11]
= 4/5 × 10/11
Using Cancellation method
= 4/1 × 2/11
= 8/11
3.8 3/4 multiplied by 2/9
= 8 3/4 × 2/9
= 27/4 × 2/9
= 3/2 × 1/1
= 3/2
= 1 1/2
4. [4/5]10/11][7/8]
40/50 ÷ 77/88
= 40/50 × 88/77
= 40/50 × 8/7
= 40/25 × 4/7
= 8/5 × 4/7
= 32/35
Answer:
I am going to show you the first steps to complete squares for the given equation: 1) Starting equation: 3x^2 + 9x -4 = 0 2) Add 4 to both sides => 3x^2 + 9x - 4 + 4 = 4 => 3x^2 + 9x = 4 3) Extract common factor 3 in the left side => 3 (x^2 + 3x). Now, compare with a(x^2 + 3x) and you get a = 3. Answer: a = 3.
19+4n is the answer and i m sure
Answer:
the youngest brother is of 2 years and 5 months
if this rule still applies, the next son will be born in 2 months.
Step-by-step explanation:
Given that:
Oldest son= 11 3/4 years old = 11 years 3/4 (12) months = 11 years 9 months
Difference = 2 years 7/12(12) months = 2 years 7 moths
So for finding the age of youngest brother:
Subtract the difference others from age of oldest:
= 11 years 9 months - 4(2 years 7 months)
= 11 years 9 months - 9 years 4 months
= 2 years 5 months
So the youngest brother is of 2 years and 5 months
if this rule still applies, the next son will be born in 2 months.
i hope it will help you!
A = {1, 2, 5, 6, 8}
{1} U {2, 5, 6, 8}
{2} U {1, 5, 6, 8}
{5} U {1, 2, 6, 8}
{6} U {1, 2, 5, 8}
{8} U {1, 2, 5, 6}
{1, 2} U {5, 6, 8}
{1, 5} U {2, 6, 8}
{1, 6} U {2, 5, 8}
{1, 8} U {2, 5, 6}
{1, 2, 5} U {6, 8}
{1, 2, 6} U {5, 8}
{1, 2, 8} U {5, 6}
{1, 5, 6} U {2, 8}
{1, 5, 8} U {2, 6}
{1, 6, 8} U {2, 5}
The answer is 15 distinct pairs of disjoint non-empty subsets.
