Answer:
Question 1. (2.2, -1.4)
Question 2. (1.33, 1)
Step-by-step explanation:
Equations for the given lines are
-----(1)
It is given that this line passes through two points (0, 2.5) and (2.2, 1.4).
------(2)
This equation passes through (0, -3) and (2.2, -1.4).
Now we have to find a common point through which these lines pass or solution of these equations.
From equations (1) and (2),
x =
x = 2.2
From equation (2),
y = -1.4
Therefore, solution of these equations is (2.2, -1.4).
Question 2.
The given equations are y = 1.5x - 1 and y = 1
From these equations,
1 = 1.5x - 1
1.5x = 2
x =
Therefore, the solution of the system of linear equations is (1.33, 1).
I'm sorry, but what digit is underlined?
Answer:
23.1% probability of meeting at least one person with the flu
Step-by-step explanation:
For each encounter, there are only two possible outcomes. Either the person has the flu, or the person does not. The probability of a person having the flu is independent of any other person. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.
Infection rate of 2%
This means that 
Thirteen random encounters
This means that 
Probability of meeting at least one person with the flu
Either you meet none, or you meet at least one. The sum of the probabilities of these outcomes is 1. So

We want
. Then

In which



23.1% probability of meeting at least one person with the flu
<span>45% -------------------------------chance that the land has oil
then
55</span>%--------------------------------chance that the land not have oil
<span>80% -------------------accuracy rate of indicating oil in the soil. (if land does have oil)
20</span>% -------------------accuracy rate of indicating not oil in the soil. (if land does have oil)
20% ---------------------accuracy rate of indicating oil in the soil. (if land has not oil)
80% ---------------------accuracy rate of indicating not oil in the soil. (if land has not oil)
that the land has no oil----------------55%
the test shows that it has oil-------- 20%
then 0.55*0.20=0.11=11%
the probability that the land has no oil and the test shows that it has oil is 11%