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VARVARA [1.3K]
2 years ago
13

A previous analysis of paper boxes showed that the the standard deviation of their lengths is 9 millimeters. a packer wishes to

find the 98% confidence interval for the average length of a box. how many boxes does he need to measure to be accurate within 3 millimeters?
Mathematics
1 answer:
maksim [4K]2 years ago
7 0
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Evaluate the expression. P(9, 3) · P(5, 4)
boyakko [2]

Answer:

P(9,3) *P(5,4)

And if we use the permutation formula given by:

nPx = \frac{n!}{(n-x)!}

And replacing we got:

\frac{9!}{6!} \frac{5!}{4!}= 504*5 = 2520

Step-by-step explanation:

For this problem we want to find the following expressionÑ

P(9,3) *P(5,4)

And if we use the permutation formula given by:

nPx = \frac{n!}{(n-x)!}

And replacing we got:

\frac{9!}{6!} \frac{5!}{4!}= 504*5 = 2520

6 0
2 years ago
A composite figure is comprised of a square and 4 semicircles. How can you decompose the composite figure to determine its area?
tangare [24]

Answer:

As a square and four semi circles

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
ALL THE POINTS!! (01.01 LC) What is the rational number equivalent to 3 point 12 with a bar over 12? (1 point) 3 and 4 over 33 3
saul85 [17]

Answer:

A is the answer

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
You drive 30 miles due east in a half hour. Then, you turn left and drive 30 miles north in 1 hour. What are your average speed
garri49 [273]
Original position: P1=(0,0)
<span>You drive 30 miles due east in a half hour: x=+30 miles, t1=1/2 hour=0.5 hours
</span><span>Then, you turn left and drive 30 miles north in 1 hour: y=+30 miles, t2=1 hour
Rectangular coordinates of final position: P2=(x,y)→P2=(30,30)
Total time: t=t1+t2=0.5 hours+1 hour→t=1.5 hours

Average speed: S ave=d/t
Total distance: d=x+y=30 miles+30 miles→d=60 miles
S ave = 60 miles / (1.5 hours)
S ave = 40 miles/hour

Velocity is a vector, the magnitude of this vector is the magnitude of the vector of change of position dividing by the total time t
The vector of change of position: s=P1-P2=(30,30)-(0,0)=(30-0,30-0)→
s=(30,30) 
Magnitude of vector s=sqrt[30^2+30^2]=sqrt[30^2*2]=sqrt[30^2]*sqrt(2)
Magnitude of vector s=30*sqrt(2) miles

Magnitude of velocity vector = Magnitud of vector s / t
Magnitude of velocity vector = [30*sqrt(2) miles] / (1.5 hours)
Magnitude of velocity vector = 20*sqrt(2) miles / hour
Magnitude of velocity vector=20*1.4142 miles / hour
Magnitude of velocity vector=28.284 miles/hour

Polar coordinates of your position=(r, theta)
r=Magnitude of vector s=30*sqrt(2) miles
theta=tan^(-1) (y/x) = tan^(-1) [(30 miles) / (30 miles)]
theta=tan^(-1) (1)→theta=45°=Pi/4 (Pi=3.1416)
Polar coordinates of your position: ( 30*sqrt(2) miles, 45°)
Polar coordinate of your position: ( 30*sqrt(2) miles, Pi/4 )

Answers:
Average speed: 40 miles / hour
Velocity: 20*sqrt(2) miles / hour = 28.284 miles / hour
Rectangular coordinates of your position = (30,30)
Polar coordinates of your position=(30*sqrt(2) miles,45°)
Polar coordinates of your position=(30*sqrt(2) miles,Pi/4)</span>
4 0
1 year ago
Side AB of square ABCD is parallel to the Y axis and the perimeter of ABCD is 36. If the coordinates of point B is (5,17) . What
Zarrin [17]
<h3>Answer: (C) (14,8)</h3>

============================================

Explanation:

The perimeter of the square is 36, so each side length is 36/4 = 9 units.

Point B is located at (5,17). We move down 9 units to get to (5,8), which is the location of point A. Then we move 9 units to the right to arrive at (14,8) which is point D's location.

Or we could go from B = (5,17) to C = (14,17) and then to D = (14,8). Each time we move 9 units.

8 0
1 year ago
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