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2 years ago

5

Sam and chad are ticket-sellers at their class play. sam is selling student tickets for $2.00 each, and chad selling adult ticke

ts for $5.50 each. if their total income for 24 tickets was $83.00, how many tickets did sam sell?

1 answer:

Nikolay [14]2 years ago

3 0

15 adult tickets, or 41 children tickets. but combined it could be, 13 adults and 5 children tickets.

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The area of a rectangular painting is given by the trinomial x2 + 4x - 21. What are the possible dimensions of the painting? Use

zloy xaker [14]

To find the dimensions you can just factor the equation...

x^2+4x-21

x^2-3x+7x-21

x(x-3)+7(x-3)

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Data show that men between the ages of 20 and 29 in a general population have a mean height of 69.3 inches, with a standard dev

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Data show that men between the ages of 20 and 29 in a general population have a mean height of 69.3 inches, with a standard deviation of 2.5 inches. a baseball analyst wonders whether the standard deviation of heights of major-league baseball players is less than 2.5 inches. the heights (in inches) of 20 randomly selected players are shown in the table.

72 74 71 72 76

70 77 75 72 72

77 72 75 70 73

74 75 73 74 74

What are the correct hypotheses for this test?

The null hypothesis is H₀?: ____ 2.5

The alternative hypothesis is H₁?: ____ 2.5

Calculate the value of the test statistic.

x² = _____ (Round to three decimal places)

Answer:

Null hypothesis, H₀: σ = 2.5

Alternative hypothesis, Hₐ: μ<2.5

Test statistic = 12.920

Step-by-step explanation:

Given Data shows that:

men between the ages of 20 and 29 in a general population have a mean height of 69.3 inches, with a standard deviation of 2.5 inches

We consider a random sample of 20 selected baseball players.

Therefore;

The Null and Alternative hypothesis are as follows:

The Null hypothesis is the standard deviation of the heights of major league baseball players is not less than 2.5 inches.

Null hypothesis, H₀: σ = 2.5

On the other hand: The Alternative hypothesis is the standard deviation of the heights of major league baseball players is less than 2.5 inches.

Alternative hypothesis, Hₐ: μ<2.5

The Mean Calculation is:

$\bar{x} = \frac{1}{2} \sum x_i$

$= \frac{1}{20} (72+74+...+74) \\ \\ = \frac{1468}{20} \\ \\ =73.4$

The sample standard deviation is:

$s = \sqrt{\frac{1}{n-1} \sum (x_1 - \bar{x})^2 }$

$= \sqrt{\frac{1}{20-1} \sum (72-73.4)^2 + ...+(74-73.4)^2 } \\ \\ = \sqrt{4.25} \\ \\ = 2.06$

The test statistics is now determined as :

$x^2 = \frac{(n-1)s^2}{\sigma^2} \\ \\ = \frac{(20-1)(2.06)^2}{(2.5)^2} \\ \\ = \frac{19*4.25}{6.25} \\ \\ = \frac{80.75}{6.25} \\ \\ = 12.920$

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2 years ago

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Find the difference between the cash price and the payment plan and calculate the interest rate for the following questions.

vagabundo [1.1K]

Answer:

1).

Difference = $6

Interest rate= 4.03%

2).diffrence = $97

Interest rate = 14.37%

3). Difference = $7

Interest rate= 4.67%

4). difference= 191

Interest rate= 9.6%

5). Difference= 2.25

Interest rate= 3%

6). Difference=$ 302

Interest rate=9.12%

Step-by-step explanation:

1).$10 per months for 15 months

= 10*15=$150

PLus a down payment of $5= $155

Interest = 155-149= $6

Interest rate = 6/149*100= 4.03%

2.)$120.00 per month for 6 months

= 120*6=$ 720

Plus a down payment of $52=$772

Interest= 772-675= $97

Interest rate = 97/675 *100= 14.37%

3). $12.00 per month for 11 months

= 12*11= 132 plus down payment of $25

= $157

Interest= 157-150= $7

Interest rate=7/150 *100= 4.67%

4).$74.00 per month for 24 months

= 74*24=$1776

Plus a down payment of $400=$ 2176

Interest= 2176-1985= 191

Interest rate= 191/1985*100= 9.6%

5).$4.75 per week for 11 weeks

= 4.75*11=$52.25

Plus a down payment if $25

= 25+52.25=$ 77.25

Interest= 77.25-75= 2.25

Interest rate= 2.25/75 *100= 3%

6).$300 a month for 10 months

= 300*10= $3000

Plus a down payment of $600

= $3600

Interest=3600-3298= 302

Interest rate= 302/3298 *100=9.12%

5 0

2 years ago

Find the standard deviation of the following data. Answers are rounded to the nearest tenth. 5, 5, 6, 12, 13, 26, 37, 49, 51, 56

kogti [31]

Answer:

24.2(to the nearest tenth)

Step-by-step explanation:

The question is ungrouped data type

standard deviation =√ [∑ (x-μ)² / n]

mean (μ)=∑x/n

= $\frac{5+5+6+12+13+26+37+49+51+56+56+84}{12}$

=33.3

x-μ for data 5, 5, 6, 12, 13, 26, 37, 49, 51, 56, 56, 84 will be

-28.3, -28.3, -27.3, -21.3, -7.3, 3.7, 15.7,17.7, 22.7,22.7,50.7

(x-μ)² will be 800.89, 800.89,745.29,453.69,53.29,13.69,246.49,313.29,515.29,515.29,2570.49

∑ (x-μ)² will be = 7028.59

standard deviation = √(7028.59 / 12)

=24.2

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2 years ago