This is a classic math problem, and it is not solved in a normal way.
<span>1+4=5
2+5=12
3+6=21
8+11=?
There is a pattern that can be spotted. 2+5 does not equal twelve, however 2*(2+5) does equal 12. Below is how to solve the rest of the equations:
</span>1+4=5 -> 1*(4+1)=5
2+5=12 -> 2*(5+1)=12
3+6=21 -> <span>3*(6+1)=21 </span>
8+11=? -> <span>8*(11+1)=96
</span>
This is one way to answer the problem, HOWEVER there is another way to answer the problem that gives the SAME answer, but many people mistakenly believes it gives a different answer. If anyone tries to post the other way of doing this problem, but tells you the answer is 40, please comment on this post or message me and let me know. I will explain why the answer is actually 96 either way.
Answer:

Step-by-step explanation:
Assuming that a fair die is rolled.
- The sample space is 1, 2, 3, 4, 5, 6 and all the outcomes are equally likely.
Let X be the set of all possible outcomes. Let A be an outcome.
So, the probability that A occurs is:

As the set of all possible outcomes of the roll of a single die is:

Observe that

Here
because 8 is not in the set sample space. So, the outcome of occurring the number 8 is not possible from the all possible outcomes.
So, the probability must be zero.
In other words,


Therefore,

Answer:
a.
x + y = 60
x = y + 30
b.
substitution:
(y + 30) = y = 60
2y + 30 = 60
2y = 30
y = 15
15 minutes for freehand
c.
No, because if he spends 40 minutes on the treadmill, he would have spent 10 minutes for freehand exercises. His total time in the gym would be 50 minutes, not 60.
Answer:
The lengths of the sides are 2.2 ft and 4.5 ft
Step-by-step explanation:
Let
a -----> the length of one side of the mosaic
b ----> the length of the other side of the mosaic
c ----> the hypotenuse of the mosaic
we know that
Applying the Pythagoras Theorem
-----> equation A
we have
-----> equation B
-----> equation C
substitute equation B and equation C in equation A and solve for b



Find the value of a
------> 
therefore
The lengths of the sides are 2.2 ft and 4.5 ft
Answer:
0.3114
Option d is right
Step-by-step explanation:
Let X be the time spent on a treadmill in the health club
Given that research shows that on average, patrons spend an average of 42.5 minutes on the treadmill, with a standard deviation of 5.4 minutes
Also given that X is normal
the probability that randomly selected individual would spent between 30 and 40 minutes on the treadmill.

round off to two decimals tog et
the probability that randomly selected individual would spent between 30 and 40 minutes on the treadmill is 0.31
Hence option d is right