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Komok [63]
2 years ago
6

In a health club, research shows that on average, patrons spend an average of 42.5 minutes on the treadmill, with a standard dev

iation of 5.4 minutes. It is assumed that this is a normally distributed variable. Find the probability that randomly selected individual would spent between 30 and 40 minutes on the treadmill.
a. 0.38
b. 0.69
c. 0.99
d. 0.31
Mathematics
1 answer:
Paha777 [63]2 years ago
3 0

Answer:

0.3114

Option d is right

Step-by-step explanation:

Let X be the time spent on a treadmill in the health club

Given that  research shows that on average, patrons spend an average of 42.5 minutes on the treadmill, with a standard deviation of 5.4 minutes

Also given that X is normal

the probability that randomly selected individual would spent between 30 and 40 minutes on the treadmill.

= P(30

round off to two decimals tog et

the probability that randomly selected individual would spent between 30 and 40 minutes on the treadmill is 0.31

Hence option d is right

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Researchers from Dartmouth Medical School conducted a study in 2003 to look at the connection between watching actors smoking in
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Answer:

The 95% confidence interval for the proportion of adolescents who tried smoking for the first time because of exposure to smoking in the movies is (0.37, 0.40).

Step-by-step explanation:

A confidence interval is an interval estimate of the population parameter. The confidence interval has a certain probability of consisting the true value of the parameter.

The (1 - <em>α</em>) % confidence interval for the population proportion (<em>p</em>) is given by:

CI=\hat p\pm z_{\alpha/2}\times \sqrt{\frac{\hat p(1-\hat p)}{n}}

The information provided is:

n = 6522\\\hat p=0.38\\z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

*Use a <em>z</em>-table for the critical value.

Construct the 95% confidence interval for the proportion of adolescents who tried smoking for the first time because of exposure to smoking in the movies as follows:

CI=\hat p\pm z_{\alpha/2}\times \sqrt{\frac{\hat p(1-\hat p)}{n}}\\=0.38\pm 1.96\times \sqrt{\frac{0.38(1-0.38)}{6522}}\\=0.38\pm 0.0118\\=(0.3682, 0.3918)\\\approx (0.37, 0.40)

Thus, the 95% confidence interval for the proportion of adolescents who tried smoking for the first time because of exposure to smoking in the movies is (0.37, 0.40).

8 0
1 year ago
An oblong box has a volume equal to lwh, where l is the length, w is the width, and h is the height. If the volume is 24 cubic f
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<span>An oblong box has a volume equal to lwh, where l is the length, w is the width, and h is the height. If the volume is 24 cubic feet, solve for the height in terms of the other sides.

Given:
volume of 24 cubic feet

Required:
height

Solution:
V = 24 cubic feet
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24 = l^3
l = 2.88 feet</span>
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2 years ago
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For this case we have the following equation:
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2 years ago
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Evaluate 4-0.25g+0.5h4−0.25g+0.5h4, minus, 0, point, 25, g, plus, 0, point, 5, h when g=10g=10g, equals, 10 and h=5h=5h, equals,
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I believe the correct given equation is in the form of:

4 – 0.25 g + 0.5 h

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g = 10 and h = 5

What this actually means is that to evaluate simply means to calculate for the value of the equation by plugging in the values of the variables. Therefore:

4 – 0.25 g + 0.5 h = 4 – 0.25 (10) + 0.5 (5)

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Third, since our fraction is not in the simplest form, we can simplify it down by listing the factors of both the numerator and denominator and then finding the greatest common factor (GCF). 

Factors of 21: 1, 3, 7, 21
Factors of 36: 1, 2, 3, 4, 6, 9, 12, 18, 36

The GCF is 3, since only 1 and 3 were the common factors and since 3 is the greatest common factor. 

Fourth, now we can divide our numerator (21) and denominator (36) by our recently found GCF which was 3. 

21 \div 3 = 7 \\ 36 \div 3 = 12

Our new fraction in its simplest form is 7/12.

Answer in fraction form: \fbox {7/12}
Answer in decimal form: \fbox {0.5833}
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