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2 years ago

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What would the inter-rater reliability be for a 50-item measure in which the number of agreements between Rater 1 and Rater 2 wa

s 45?
A) 0.45
B) 80%
C) 0.90
D) 95%

1 answer:

nlexa [21]2 years ago

7 0

What would the inter-rater reliability be for a 50-item measure in which the number of agreements between Rater 1 and Rater 2 was 45?
C) 0.90

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What is the quotient of -8a^8b^-2/ 10a^-4b^-10 in simplified form?

postnew [5]

Here are a few rules with exponents that you need to know:

Dividing exponents of the same base: $\frac{x^m}{x^n}=x^{m-n}$

For this, divide:

$\frac{-8a^8b^{-2}}{10a^{-4}b^{-10}}=\frac{-8}{10}a^{8-(-4)}b^{-2-(-10)}=-\frac{4}{5}a^{12}b^8$

<u>Your final answer is $-\frac{4}{5}a^{12}b^8$ </u>

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2 years ago

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PLS HELP ASAP I WILL IVE BRAINLIST ANSWER!!!!!Leon verified that the side lengths 21, 28, 35 form a Pythagorean triple using thi

Juliette [100K]

Answer:

Leon is correct. (Option 1)

Step-by-step explanation:

Given that Leon verified that the side lengths 21, 28, 35 form a Pythagorean triple using this procedure.

Step 1: Find the greatest common factor of the given lengths: 7

Step 2: Divide the given lengths by the greatest common factor: 3, 4, 5

Step 3: Verify that the lengths found in step 2 form a Pythagorean triple.

we have to explain whether or not Leon is correct.

As, 3,4,5 forms a Pythagorean triplet i.e satisfies the Pythagoras theorem

$Hypotenuse^2=Base^2+Perpendicular^2$

⇒ $5^2=3^2+4^2$

Let a, b, c forms a Pythagorean triplet

$a^2+b^2=c^2$

Multiplied by 4 on both sides

⇒ $4a^2+4b^2=4c^2$

⇒ ${2a}^2+{2b}^2={2c}^2$

Hence, we say 4a, 4b and 4c also forms a Pythagorean triplet.

∴ multiplying every length of a Pythagorean triple by the same whole number results in a Pythagorean triple.

Hence, Leon is correct.

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2 years ago

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Diego has some money in his bank account before he starts a summer job. He deposits the money from the summer job in his bank ac

chubhunter [2.5K]

Answer:

it should be $23

Step-by-step explanation:

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2 years ago

There are 200 students in eleventh grade high school class. There are 40 students in the soccer team and 50 students in the bask

bekas [8.4K]

Answer:

P(A) = 0.2

P(B) = 0.25

P(A&B) = 0.05

P(A|B) = 0.2

P(A|B) = P(A) = 0.2

Step-by-step explanation:

P(A) is the probability that the selected student plays soccer.

Then:

$P(A)=\dfrac{40}{200}=0.2$

P(B) is the probability that the selected student plays basketball.

Then:

$P(B)=\dfrac{50}{200}=0.25$

P(A and B) is the probability that the selected student plays soccer and basketball:

$P(A\&B)=\dfrac{10}{200}=0.05$

P(A|B) is the probability that the student plays soccer given that he plays basketball. In this case, as it is given that he plays basketball only 10 out of 50 plays soccer:

$P(A|B)=\dfrac{P(A\&B)}{P(B)}=\dfrac{10}{50}=0.2$

P(A | B) is equal to P(A), because the proportion of students that play soccer is equal between the total group of students and within the group that plays basketball. We could assume that the probability of a student playing soccer is independent of the event that he plays basketball.

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2 years ago

A firm has a revenue function that can be represented by r (x)=700x-0.35x^2, where r (x) is the total revenue (in dollars) and x

Fudgin [204]

Answer:

How many units need to be sold to produce the maximum revenue? 1000 units

How many in dollars is the maximum revenue when the maximum of units are sold? $350,000

Step-by-step explanation:

We get max value of a function if we differentiate it and set it equal to 0.

We need to differentiate r(x) and set it equal to 0 and solve for x.

<u><em>That would be number of units sold to get max revenue.</em></u>

<u><em /></u>

<u>Then we take that "x" value and substitute into r(x) to get the max revenue amount.</u>

<u />

Before differentiating, we see the rules shown below:

$f(x)=ax^n\\f'(x)=n*ax^{n-1}$

Where

f'(x) is the differentiated function

Now, let's do the process:

$r (x)=700x-0.35x^2\\r(x)=700-2*0.35x\\r(x)=700-0.7x\\0=700-0.7x\\0.7x=700\\x=1000$

So, 1000 units need to be sold for max revenue

Now, substituting, we get:

$r (x)=700x-0.35x^2\\r(1000)=700(1000)-0.35(1000)^2\\r(1000)=350,000$

The max revenue amount is $350,000

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2 years ago