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ad-work [718]
1 year ago
13

Find the area of trapezoid $DUCK$ shown below. [asy] unitsize(2mm); defaultpen(linewidth(.7pt)+fontsize(10pt)); pair D=(0,0), U=

(5,12), C=(20,12), K=(36,0), F=(5,0); draw(D--U--C--K--cycle); draw(U--F,linetype("8 4")); draw(rightanglemark(U,F,K,25)); label("$D$",D,SW); label("$U$",U,N); label("$C$",C,NE); label("$K$",K,SE); label("5",midpoint(D--F),S); label("13",midpoint(D--U),NW); label("15",midpoint(U--C),N); label("20",midpoint(C--K),NE); [/asy]
Mathematics
1 answer:
Agata [3.3K]1 year ago
6 0

Answer:

306 sq. units

Step-by-step explanation:

<u>Coordinates of the trapezoid:</u>

  • D(0, 0), U(5, 12), C(20, 12), K(36, 0)

<em>Area of trapezoid = 1/2(Base1 + Base2)*Height</em>

<u>Bases have length of:</u>

  • 36 - 0= 36 units and
  • 20 - 5 = 15 units

<u>Height is:</u>

  • 12 - 0 = 12 units

<u>Area:</u>

  • 1/2(36+15)*12 = 306 sq. units
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