Since the range of the scores given was between 300 and 700 (which is 2 standard deviations below and above the mean), the probability that a randomly selected student's math score - as based on the empirical rule of statistics - is 95%. In decimal form, it is .95.
Answer:
a) 90.695 lb
b) 85.305 lb
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

(a) The 65th percentile
X when Z has a pvalue of 0.65. So X when Z = 0.385.




(b) The 35th percentile
X when Z has a pvalue of 0.35. So X when Z = -0.385.




Answer:
Solution-
We know that,
Residual value = Given value - Predicted value
The table for residual values is shown below,
Plotting a graph, by taking the residual values on ordinate and values of given x on abscissa, a random pattern is obtained where the points are evenly distributed about x-axis.
We know that,
If the points in a residual plot are randomly dispersed around the horizontal or x-axis, a linear regression model is appropriate for the data. Otherwise, a non-linear model is more appropriate.
As, in this case the points are distributed randomly around x-axis, so the residual plot show that the line of regression is best fit for the data set.
Hope this helps!
Step-by-step explanation:
Answer: We can arrange the steps with help of below explanation.
Step-by-step explanation:
Here ABC is a triangle,
Draw a perpendicular from BD to side AC ( construction)
where 
In the right triangle BCD, from the definition of cosine:
cos C =CD/ BC
CD= a cos C
Subtracting this from the side b, we see that
DA= b-acos C
In the triangle BCD, from the definition of sine:
sin C =BD / a
BD = a sin C
In the triangle ADB, applying the Pythagorean Theorem
Substituting for BD and DA from (2) and (3)
⇒
( On simplification)
⇒
⇒
⇒
(because,
)