Answer:
The minimum amount of rubber needed is 1,134 square inches
Step-by-step explanation:
we know that
The surface area of a sphere (basketball ) is given by the formula
we have
----> the radius is half the diameter
substitute
Multiply by 4 (because are four basketballs)
therefore
The minimum amount of rubber needed is 1,134 square inches
<span>−24x<span>y^5</span>−15x×3<span>y^2</span>+9x×2<span>y<span>^3
</span></span></span><span><span>−24x<span>y<span>^5</span></span>−45x<span>y^<span>2</span></span>+9x×2<span>y^3</span></span><span>
</span><span><span>−24x<span>y<span><span>^5</span><span></span></span></span>−45x<span>y<span><span>^2</span><span></span></span></span>+18x<span>y<span>^3
Hope i helped^-^
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Answer:
Condition A.
A rectangle with four right angles
There can be many quadrilaterals satisfying this condition.
Condition B.
A square with one side measuring 5 inches
There can be only one quadrilateral satisfying this condition.
Condition C.
A rhombus with one angle measuring 43°
There can be many quadrilaterals satisfying this condition.
Condition D.
A parallelogram with one angle measuring 32°
There can be many quadrilaterals satisfying this condition.
Condition E.
A parallelogram with one angle measuring 48° and adjacent sides measuring 6 inches and 8 inches.
There can be only one quadrilateral satisfying this condition.
Condition F.
A rectangle with adjacent sides measuring 4 inches and 3 inches.
There can be only one quadrilateral satisfying this condition
Step-by-step explanation:
Answer:
p = $116.83/0.70 = $166.90
Step-by-step explanation:
let p represent the original price. Then:
(1.00 - 0.30)p = $116.83, or
0.70p = $116.83.
Finally,
p = $116.83/0.70 = $166.90
