Answer:
700.7
Step-by-step explanation:
You're looking for distance. So all you have to do is 18.2 x 28.5 and you'll get your answer.
Hope this helps. :)
Answer:
There is a 38.97% probability that this student earned an A on the midterm.
Step-by-step explanation:
The first step is that we have to find the percentage of students who got an A on the final exam.
Suppose 13% students earned an A on the midterm. Of those students who earned an A on the midterm, 47% received an A on the final, and 11% of the students who earned lower than an A on the midterm received an A on the final.
This means that
Of the 13% of students who earned an A on the midterm, 47% received an A on the final. Also, of the 87% who did not earn an A on the midterm, 11% received an A on the final.
So, the percentage of students who got an A on the final exam is

To find the probability that this student earned an A on the final test also earned on the midterm, we divide the percentage of students who got an A on both tests by the percentage of students who got an A on the final test.
The percentage of students who got an A on both tests is:

The probability that the student also earned an A on the midterm is

There is a 38.97% probability that this student earned an A on the midterm.
Answer:
a) 0.1829
b) 0.6823
c) 0.0413
Step-by-step explanation:
We are given the following information:
We treat adult having little confidence in the newspaper as a success.
P(Adult have little confidence) = 62% = 0.62
Then the number of adults follows a binomial distribution, where
where n is the total number of observations, x is the number of success, p is the probability of success.
Now, we are given n = 10
a) exactly 5
0.1829 is the probability that exactly 5 out of 10 U.S.adults have very little confidence in newspapers.
b) atleast six
0.6823 is the probability that atleast 6 out of 10 U.S. adults have very little confidence in newspapers.
c) less than four
0.0413 is the probability that less than 4 out of 10 U.S. adults have very little confidence in newspapers.
The linear equation of relating two objects can be written in the form,
y = ax + b
Our x is the number of passenger and y is the weight (in tons). Using the first two conditions,
10 = 60(a) + b
13 = 84(a) + b
The values of a and b from the equations are 0.125 and 2.5.
For 50-passenger bus,
y = (50)(0.125) + 2.5
The value of y is 8.75.
6.842 or higher. When you line up the decimals, you see 6.842 has a 2 and 6.841 has a 1. 2 is greater than 1, more greater numbers are 6.843, 6.844, 6.845, etc.