Point S makes the two connected angles the same. They both have right angles.
And one side of each is congruent.
This means you know 2 angles are the same and one side is the same.
You would use ASA (Angle, Side, Angle)
Answer: 0.46, 0.056, the distribution is approximately normal
Step-by-step explanation: The shape is approximately normal since the expected number of successes equals 36.8 and the expected number of failures equals 43.2 are both larger than 10
Answer:
Step-by-step explanation:
We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean
For the null hypothesis,
µ = 17
For the alternative hypothesis,
µ < 17
This is a left tailed test.
Since the population standard deviation is not given, the distribution is a student's t.
Since n = 80,
Degrees of freedom, df = n - 1 = 80 - 1 = 79
t = (x - µ)/(s/√n)
Where
x = sample mean = 15.6
µ = population mean = 17
s = samples standard deviation = 4.5
t = (15.6 - 17)/(4.5/√80) = - 2.78
We would determine the p value using the t test calculator. It becomes
p = 0.0034
Since alpha, 0.05 > than the p value, 0.0043, then we would reject the null hypothesis.
The data supports the professor’s claim. The average number of hours per week spent studying for students at her college is less than 17 hours per week.
Answer:
Percentage Rate=6%
Step-by-step explanation:
Total borrowed=$2,100
Time=3 years
Rate=?
Total amount owed after 3 years= total borrowed + simple interest
$2,478=$2,100 + x
X=$2,478 - $2,100
=$378
The simple interest=$378
Simple interest=P×R×T
Where,
P= principal=$2,100
R=Rate=?
T=Time=3 years
Simple interest=$378
Simple interest=P×R×T/100
$378=$2,100×R×3/100
$378=$6,300R/100
$378=$63R
R=$378/$63
R=6
Therefore,
Rate=6%
Answer:
< CFE = 40°
Step-by-step explanation:
To better understand the solution, see attachment for the diagram.
Given:
BC parallel to DE
Measure of Arc BD = 58°
Measure of Arc DE = 142°
First step: Draw a diameter that passes through the centre of the circle and name it. In this case, the diameter is line ST.
The line ST divides the arc BD and arc DE into half.
That is:
Arc SC = 1/2(arc BC) =1/2(58)
Arc SC = 29°
Arc TE = 1/2(arc DE) =1/2(142)
Arc TE = 71°
Arc SC + Arc CE + Arc TE = 180° (Sum of angles in a semicircle
29° + Arc CE + 71° = 180°
Arc CE + 100° = 180°
Arc CE = 180-100
Arc CE = 80°
Inscribed angle = 1/2(intercepted angle)
<CFE = 1/2(Arc CE )
<CFE = 1/2(80)
< CFE = 40°
