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sdas [7]
1 year ago
6

The country of Freedonia has decided to reduce its carbon-dioxide emission by 35\%35%35, percent each year. This year the countr

y emitted 404040 million tons of carbon-dioxide.
Write a function that gives Freedonia's carbon-dioxide emissions in million tons, E(t)E(t)E, left parenthesis, t, right parenthesis, ttt years from today.
Mathematics
2 answers:
miskamm [114]1 year ago
7 0

Answer:

The quantity after t years 40 (0.65)^{\textrm t} millions tons

Step-by-step explanation:

Given as :

The rate of decrease of carbon dioxide each other = 35%

The quantity of carbon dioxide emitted this year = 40 million tons

Let the quantity of carbon dioxide emitted after t year = A millions tons

Now, According to question

The quantity of carbon dioxide emitted after t year = The quantity of carbon dioxide emitted this year ×

Or, A millions tons = 40 millions tons ×

Or, A millions tons = 40 millions tons ×

Or, A millions tons = 40 millions tons ×

julia-pushkina [17]1 year ago
6 0

Answer:

At t years, the composition of carbon dioxide is 45 * 0.35^(t - 1) million tons

Step-by-step explanation:

Given

Current composition of carbon dioxide = 40million tons

Rate of reduction = 35%

Time = t years

The question is an arithmetic progression, asking is to calculate the nth term

To solve this, we make use of the geometric progression formula of nth term

Tn = a,r^(n-1)

Where a = first term

n = expected term

r = common ratio.

In this case

a = 45 million

r = 35% = 0.35

n = t

By substituton

At t years, the composition of carbon dioxide is 45 * 0.35^(t - 1) million tons

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Bill manages the quality department. His people check parts made by the production departments to assure all specifications are
OLga [1]

Answer:

Option B: Bill is​ a staff manager

Step-by-step explanation:

Bill manages the quality department. His people check parts made by the production departments to assure all specifications are met. Bill is​ - a staff manager.

Other duties of staff managers are :

He is in charge person that consumes revenue

He guides the line manager.

He helps to take decisions.

He assists line persons and help the top management in various business activities.

He also takes care of the line management and top management. Etc.

7 0
1 year ago
What is 4 square root of 81 to the fifth power in exponential form
creativ13 [48]

Answer:

B is the answer.

Step-by-step explanation:

x^{\frac{m}{n} }  = \sqrt[n]{x^{m} }  

\sqrt[4]{81^{5} } =  81^{\frac{5}{4} }

5 0
2 years ago
How much power is produced by a flashlight that has a voltage of 12 volts and a current of 6.5 × 10-2 amps?
Jlenok [28]

Answer:

0.78 Watts is correct answer.

Step-by-step explanation:

Formula:  

P=V*I  

=12*(6.5*10^-2)  

= 12*0.065  

=0.78 Watt.  

3 0
1 year ago
Read 2 more answers
If e = 9 cm and f = 40 cm, what is the length of g?
rewona [7]

(9,40,41) is a Pythagorean Triple, farther down the list than teachers usually venture.

Answer: D. 41 cm

There's a subset of Pythagorean Triples where the long leg is one less than the hypotenuse,

a^2+b^2 = (b+1)^2

a^2 + b^2 = b^2 + 2b +1

a^2=2b+1

So we get one for every odd number, since the square of an odd number is odd and the square of an even number is even.

b = (a^2 - 1)/2

a=3, b=(3^2-1)/2=4, c=b+1=5

a=5, b=(5^2-1)/2 =12, c = 13

a=7, b=24, c=25

a=9, b=40, c=41

a=11, b=60, c=61

a=13, b=84, c=85

It's good to be able to recognize Pythagorean Triples when we see them.  

Otherwise we'd have to work the calculator:

√(9² + 40²) = √1681 = 41

8 0
2 years ago
Last year, 46% of business owners gave a holiday gift to their employees. A survey of business owners indicated that 35% plan to
DiKsa [7]

Answer:

a) Number = 60 *0.35=21

b) Since is a left tailed test the p value would be:  

p_v =P(Z  

c) If we compare the p value obtained and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% the proportion of business owners providing holiday gifts had decreased from the 2008 level.  

We can use as smallest significance level 0.044 and we got the same conclusion.  

Step-by-step explanation:

Data given and notation  

n=60 represent the random sample taken

X represent the business owners plan to provide a holiday gift to their employees

\hat p=0.35 estimated proportion of business owners plan to provide a holiday gift to their employees

p_o=0.46 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Part a

On this case w ejust need to multiply the value of th sample size by the proportion given like this:

Number = 60 *0.35=21

2) Part b

We need to conduct a hypothesis in order to test the claim that the proportion of business owners providing holiday gifts had decreased from the 2008 level:  

Null hypothesis:p\geq 0.46  

Alternative hypothesis:p < 0.46  

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.35 -0.46}{\sqrt{\frac{0.46(1-0.46)}{60}}}=-1.710  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v =P(Z  

Part c

If we compare the p value obtained and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% the proportion of business owners providing holiday gifts had decreased from the 2008 level.  

We can use as smallest significance level 0.044 and we got the same conclusion.  

8 0
2 years ago
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