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m_a_m_a [10]
1 year ago
11

ellen buys 24 ounces of green beans at the grocery store. the green beans cost $1.90 per pound. how much does she pay for the gr

een beans, before tax?
Mathematics
1 answer:
RideAnS [48]1 year ago
7 0

Answer:

  $2.85

Step-by-step explanation:

The price Ellen pays can be found using the proportion ...

  price/(24 oz) = $1.90/(16 oz)

Multiplying by 24 oz, we get ...

  price = $1.90(24/16) = $2.85

Ellen pays $2.85 for the beans.

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Tesla wanted to determine the average miles per kWh that their vehicles get across all models and variations. They took a sample
LiRa [457]

Answer:

\mu_{\bar x} = \mu = E(X) =30KWh

\sigma_{\bar X}= \frac{\sigma}{\sqrt{n}}=\frac{3}{\sqrt{100}}=0.3

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

For this case we select a sample of n =100

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

So then the sample mean would be:

\mu_{\bar x} = \mu = E(X) =30KWh

And the standard deviation would be:

\sigma_{\bar X}= \frac{\sigma}{\sqrt{n}}=\frac{3}{\sqrt{100}}=0.3

6 0
1 year ago
Let f(x)=4x-1 and g(x)=2x^2+3. Perform each function operations and then find the domain.
Triss [41]
F(x) = 4x - 1
g(x) = 2x² + 3

1. (f + g)(x) = (4x - 1) + (2x² + 3)
    (f + g)(x) = 2x² + 4x + (-1 + 3)
    (f + g)(x) = 2x² + 4x + 2
    Domain: {x| -∞ < x < ∞}, (-∞, ∞)

2. (f - g)(x) = (4x + 1) - (2x² + 3)
    (f - g)(x) = 4x + 1 - 2x² - 3
    (f - g)(x) = -2x² + 4x + 1 - 3
    (f - g)(x) = -2x² + 4x - 2
    Domain: {x|-∞ < x < ∞}, (-∞, ∞)
3. (g - f)(x) = (2x² + 3) - (4x - 1)
    (g - f)(x) = 2x² + 3 - 4x + 1
    (g - f)(x) = 2x² - 4x + 3 + 1
    (g - f)(x) = 2x² - 4x + 4
    Domain: {x| -∞ < x < ∞}, (-∞, ∞)

4. (f · g)(x) = (4x + 1)(2x² + 3)
    (f · g)(x) = 4x(2x² + 3) + 1(2x² + 3)
    (f · g)(x) = 4x(2x²) + 4x(3) + 1(2x²) + 1(3)
    (f · g)(x) = 8x³ + 12x + 2x² + 3
    (f · g)(x) = 8x³ + 2x² + 12x + 3
    Domain: {x| -∞ < x < ∞}, (-∞, ∞)

5. (\frac{f}{g})(x) = \frac{4x - 1}{2x^{2} + 3}
    Domain: 2x² + 3 ≠ 0
                         - 3  - 3
                        2x² ≠ 0
                         2      2
                          x² ≠ 0
                           x ≠ 0
                  (-∞, 0) ∨ (0, ∞)

6. (\frac{g}{f})(x) = \frac{2x^{2} + 3}{4x - 1}
    Domain: 4x - 1 ≠ 0
                      + 1 + 1
                        4x ≠ 0
                         4     4
                         x ≠ 0
                (-∞, 0) ∨ (0, ∞)
6 0
1 year ago
During a field trip, 60 students are put into equal-sized groups. Describe two ways to interpret 60÷5 60 ÷ 5 in this context. Fi
Afina-wow [57]

The second question:

Consider the division expression 7\frac{1}{2} / 2. Select all multiplication equations that correspond to this division expression.

2 * ? = 7\frac{1}{2}     7\frac{1}{2} * ?= 2     ? * 2  = 7\frac{1}{2}

2* 7\frac{1}{2} = ?    ?  * 7\frac{1}{2} = 2

Answer:

1. See Explanation

2. 2 * ? = 7\frac{1}{2}     and     ? * 2  = 7\frac{1}{2}

Step-by-step explanation:

Solving (a):

Given

Students = 60

Group = Equal\ Sized

Required

Interpret \frac{60}{5} in 2 ways

<u>Interpretation 1:</u> Number of groups if there are 5 students in each

<u>Interpretation 2:</u> Number of students in each group if there are 5 groups

<u>Solving the quotient</u>

Quotient = \frac{60}{5}

Quotient = 12

<u>For Interpretation 1:</u>

The quotient means: 12 groups

<u>For Interpretation 2:</u>

The quotient means: 12 students

Solving (b):

Given

7\frac{1}{2} / 2

Required

Select all equivalent multiplication equations

Let ? be the quotient of t 7\frac{1}{2} / 2

So, we have:

7\frac{1}{2}/2 = ?

Multiply through by 2

2 * 7\frac{1}{2}/2 = ? * 2

7\frac{1}{2} = ? * 2

Rewrite as:

? * 2 = 7\frac{1}{2}  --- This is 1 equivalent expression

Apply commutative law of addition:

2 * ? = 7\frac{1}{2}  --- This is another equivalent expression

8 0
1 year ago
Noah planned a parallelogram-shaped sidewalk to lead from the street to the front door of his house. He realized the walkway was
nekit [7.7K]

Answer:

Step-by-step explanation:

8 0
1 year ago
Read 2 more answers
Approximate the area under the curve y = x² from x = 2 to x = 5 using a Right Endpoint approximation with 6 subdivisions.
Tanzania [10]

Answer:

\text{Area}\,=36.75

Step-by-step explanation:

Using right estimation point simply means to form a bunch of rectangles between the two limits, x =2 and x = 5. and add the areas of all those rectangles.

There must be 6 subdivisions between 2 and 5. so, to do that:

\Delta{x}=\dfrac{5-2}{6}=0.5

the length of each subdivision is 0.5 units. That also means that the 6 rectangles in between the limits will each have the base length of 0.5 units.

So the endpoints of each subdivision from 3 to 5 will be:

\begin{tabular}{|c|c|c|c|c|}3&3.5&4&4.5&5\\\end{tabular}

By <em>right </em>endpoint approx<em>, </em>we mean that the height of the rectangles will be determined by the right endpoint of each subdivision, that is, it must be equal to the function value of the first limit.

\begin{tabular}{|c|c|c|}subdivision&$x$&height($y=x^2$)&3 to 3.5&3.5&12.25&3.5 to 4&4&16&4 to 4.5&4.5&20.25&4.5 to 5&5&25\end

Note that we have used the right-end-point of the subdivision to determine the height the rectangles.

All that's left to do now is to simply calculate the areas of the each of the rectangles. And add them up.

the base of each of the rectangle is \Delta{x}=0.5

and the height is determined in the table above.

\text{Area}\,=(0.5\times12.25)+(0.5\times16)+(0.5\times20.25)+(0.5\times25)

\text{Area}\,=0.5(12.25+16+20.25+25)

\text{Area}\,=36.75

3 0
2 years ago
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