It equals 96. hope that helped
Cincinnati
Ohio à<span>
Charlote North CA = a total of 336 miles
Cincinnati </span>à<span>
Chicago Illinois = a total of 247 miles
Perry drove from Charlote to Chicago by passing Cincinati. Find the distance she
drove.
=> Note that the distance from charlotte to Cincinnati is 365 then from
Cincinnati to Chicago is 247
=> 336 miles + 247 Miles
=> 583 miles
Penny drove for a total of 583 miles from Charlotte to Cincinnati to Chicago.
</span>
Answer:One pint and 16 quarts or one pint and four gallons
Step-by-step explanation:there are two pints in a quart and there are 4 quarts in a gallon.
Answer:the total discounted price for two dogs to be groomed is 22.75
Step-by-step explanation:
A dog groomer is offering 20% off a full groom for one dog, and 15% off for each additional dog. Normally, a full groom costs $65 for each dog.
If you decide to take your two furry friends to be groomed,
the discount on the first one would be
20/100 × 65 = 0.2 × 65 = 13
the discount on the second one would be
10/100 × 65 = 0.15 × 65 = 9.75
the total discounted price for two dogs to be groomed would be
13 + 9.75 = 22.75
Answer:
a.[144;158]$
b. The parameter estimated is the population mean of the weekly expenses on the food of American families.
Step-by-step explanation:
Hello!
The study variable for this problem is "Weekly expenses on food spent by an American family"($)
For a sample n=1014 American families the corresponding sample mean is x[bar]=$151
It is stated that for the 95%CI the margin of error is ±$7
a.
The confidence interval that estimates the population mean is constructed as the "estimator ± margin of error" for example, under a Standard Normal distribution the formula for the confidence interval is:
[x[bar]±
*(δ/√n)]
For the sample taken it is:
[151±7]
The inferior limit is 144$
The superior limit is 158$
b.
The parameter estimated is the population mean of the weekly expenses on the food of American families.
The confidence level of an interval is the probability under which it is built. This probability indicates that if they build 100 confidence intervals, we expect 95 to contain the value of the population mean we are trying to estimate.
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