Answer:
17
Step-by-step explanation:
As 2 phones are defective from a group of 98 that were checked, you can determine a percentage:
2/98= 2%
This indicates that 2% of the phones are likely to be defective and because of that you can find 2% of 850:
850*2%= 17
According to this, 17 phones are likely to be defective.
Answer:
P(A) = 0.2
P(B) = 0.25
P(A&B) = 0.05
P(A|B) = 0.2
P(A|B) = P(A) = 0.2
Step-by-step explanation:
P(A) is the probability that the selected student plays soccer.
Then:

P(B) is the probability that the selected student plays basketball.
Then:

P(A and B) is the probability that the selected student plays soccer and basketball:

P(A|B) is the probability that the student plays soccer given that he plays basketball. In this case, as it is given that he plays basketball only 10 out of 50 plays soccer:

P(A | B) is equal to P(A), because the proportion of students that play soccer is equal between the total group of students and within the group that plays basketball. We could assume that the probability of a student playing soccer is independent of the event that he plays basketball.
A number 1/10 as great as 7962 would be 796.2
You get this answer by either dividing 7,962 with 10 which gives you 769.2
Or you can multiply 7,962 with 1/10 to get 7,962/10. If you simplify then you get 796 1/5 or 796.2.
T(t) = Ts + (T₀ - Ts)exp(-kt), substituting the values:
60 = 50 + (80 - 50)exp(-25k)
10/30 = exp(-25k)
k = 0.0439 °C/min