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yarga [219]
2 years ago
12

A cylindrical rainwater tank is 1.5 m tall with a diameter of 1.4 m. What is the maximum volume of rainwater it can hold??

Mathematics
1 answer:
Ket [755]2 years ago
7 0

To work out the volume of a prism, you multiply the area of cross-section by the height (or length).

So for a cylinder, you work out the area of the circle and then multiply it by the height.

Area of circle (or cross-section) = π × radius²

                                                = π × 0.7²

                                                = 0.49π   m²

Now to get the volume of the cylinder, you times this area of the cross-section by the height of the cylinder:

Volume = 0.49π × 1.5

            = 2.3 m³  (accurate to 2 decimal places)

---------------------------------------------------------------

Answer:

The maximum volume of rainwater the cylinder can hold is:

<u> </u><u>2.3 </u><u>m³</u>

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Answer:

a) 12/25

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Step-by-step explanation:

a) The first order can go anywhere, so it has 5 possibilities out of 5. The second order can go to any distributor except the one that got the first order, so it has 4 possibilities out of 5. The third order may go to any of the 3 remaining distributors, giving us 3 chances out of 5. So the probability is 5/5*4/5*3/5 = 12/25

b) The first order, again, can go anywhere, so it has 5 out of 5. The second and third order have to go to the same distributor, so, in each case, we have only 1 option available out of 5. The probability of this event is 5/5*1/5*1/5 = 1/25

c) This event is the complementary event of the union of the other 2 events the exercise has. If neither the same distributor got all 3 orders non all orders go to different distributors, then necessarily one distributor should got 2 orders and other 1. The probability of this event is, therefore 1-12/25-1/25 = 12/25.

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A ball is launched into the sky at 19.6 feet per second from a 58.8 meter tall building. The equation for the ball's height. h,
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H represents the height of the ball at a given time, symbolised as t.
Thus, we just need to find when h = 0 so that we find when it hits the ground.

0 = -4.9t² + 19.6t + 58.8
0 = 4.9t² - 19.6t - 58.8
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0 = t² - 4t - 12
0 = (t - 6)(t + 2)

So, t = 6 or -2, but t ≠ -2, since time cannot be negative in this instance.

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y = x(3b - 7)

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\frac{y}{3b-7} =x

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x= \frac{y}{3b-7}
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Matthew ran 3/8 mile and then walked 7/10 mile. Which pair of fractions can he use to find how far he went in all? (A 15/40 and
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Before we could add these numbers, 3/8 and 7/10 need a common denominator. Both 8 and 10 go into 40.

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Hope this helps! :)
7 0
2 years ago
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