Answer:
a) 12/25
b) 1/25
c) 12/25
Step-by-step explanation:
a) The first order can go anywhere, so it has 5 possibilities out of 5. The second order can go to any distributor except the one that got the first order, so it has 4 possibilities out of 5. The third order may go to any of the 3 remaining distributors, giving us 3 chances out of 5. So the probability is 5/5*4/5*3/5 = 12/25
b) The first order, again, can go anywhere, so it has 5 out of 5. The second and third order have to go to the same distributor, so, in each case, we have only 1 option available out of 5. The probability of this event is 5/5*1/5*1/5 = 1/25
c) This event is the complementary event of the union of the other 2 events the exercise has. If neither the same distributor got all 3 orders non all orders go to different distributors, then necessarily one distributor should got 2 orders and other 1. The probability of this event is, therefore 1-12/25-1/25 = 12/25.
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H represents the height of the ball at a given time, symbolised as t.
Thus, we just need to find when h = 0 so that we find when it hits the ground.
0 = -4.9t² + 19.6t + 58.8
0 = 4.9t² - 19.6t - 58.8
0 = 49t² - 196t - 588
0 = t² - 4t - 12
0 = (t - 6)(t + 2)
So, t = 6 or -2, but t ≠ -2, since time cannot be negative in this instance.
Hence, at 6 seconds, the ball will strike the ground.
Y = 3bx - 7x
y = x(3b - 7)
Divide each side by 3b - 7 (assume that it is not zero).

Answer:
Before we could add these numbers, 3/8 and 7/10 need a common denominator. Both 8 and 10 go into 40.
8 goes into 40 five times
3/8= (3*5)/40 = 15/40
10 goes into 40 four times
7/10= (7*4)/40= 28/40
ANSWER: A) 15/40 and 28/40
Hope this helps! :)