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Rama09 [41]
2 years ago
7

When 0.3(4x – 8) – 0.5(–2.4x + 4) is simplified, what is the resulting expression?

Mathematics
1 answer:
andrew11 [14]2 years ago
8 0

Answer:

2.4x - 4.4

Step-by-step explanation:

0.3(4x – 8) – 0.5(–2.4x + 4)

1.2x - 2.4 + 1.2x -2

2.4x - 4.4

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A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 449 gram setting. It is
stealth61 [152]

Answer:

We accetp  H₀

Step-by-step explanation:

Information:

Normal distribution  

Population mean      =   μ₀  = 449

Population standard deviation  σ   unknown

Sample size   n  =  23        n < 30    we use t-student test

so   n  =  23    degree of fredom   df = n  - 1  df  = 23- 1   df = 22

Sample mean    μ =  448

Sample standard deviation   s  =  20

Significance level  α  =  0,05  

1.-Hypothesis Test

Null hypothesis                               H₀     μ₀  =  449

Alternative hypothesis                    Hₐ     μ₀  ≠  449

Problem statement ask for determine decision rule for rejecting the null hypothesis. For rejecting the null hypothesis we have to  get an statistic parameter wich implies  that μ is bigger or smaller than μ₀

2.-Significance level   α  =  0,05  ;  as we have a two tail test

α/2    =  0,025

Then from t - student table for  df =  22   and 0,025 (two tail-test)

t(c)  =  ±  2.074

3.- Compute  t(s)

t(s)   =  (  μ  -  μ₀ )  /  s /√n

plugging in values

t(s)   =  (448  -  449) /  20 /√23    ⇒   t(s)   =  -  1*√23 /20

t(s)   =  - 0.2398

4.-Compare t(c)   and  t(s)

t(s)  <  t(c)         - 0.2398  <  - 2.074

Therefore  t(s)  in inside acceptance region.  We accept  H₀

7 0
2 years ago
I rent a gym for $150.00 for 30 students. Another time I rent the gym for $270.00 for 70 students. I need to find a fixed rate.
masha68 [24]

Answer: y = 3x + 60

<u>Step-by-step explanation:</u>

Set up two equations and solve the system:

 270 = 70x + b

- <u>(150 = 30x + b)</u>

  120 = 40x

    3   =  x

Input "x" into one of the equations and solve for "b":

150 = 30x + b

150 = 30(3) + b

150 = 90 + b

60 = b


Equation: y = 3x + 60

This means that there is a flat fee of $60 plus a rate of $3 per student


5 0
2 years ago
The lifetime of a cheap light bulb is an exponential random variable with mean 36 hours. Suppose that 16 light bulbs are tested
photoshop1234 [79]

Answer:

P(T

Step-by-step explanation:

Previous concepts

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

P(X=x)=\lambda e^{-\lambda x}, x>0

And 0 for other case. Let X the random variable that represent "The number of years a radio functions" and we know that the distribution is given by:

X \sim Exp(\lambda=\frac{1}{16})

Or equivalently:

X \sim Exp(\mu=16)

Solution to the problem

For this case we are interested in the total T, and we can find the mean and deviation for this like this:

\bar X =\frac{\sum_{i=1}^n X_i}{n}=\frac{T}{n}

If we solve for T we got:

T= n\bar X

And the expected value is given by:

E(T) = n E(\bar X)= n \mu= 16*36=576

And we can find the variance like this:

Var(T) = Var(n\bar X)=n^2 Var(\bar X)= n^2 *\frac{\sigma^2}{n}=n \sigma^2

And then the deviation is given by:

Sd(T)= \sqrt{n} \sigma=\sqrt{16} *36=144

And the distribution for the total is:

T\sim N(n\mu, \sqrt{n}\sigma)

And we want to find this probability:

P(T< 600)

And we can use the z score formula given by:

z=\frac{T- \mu_T}{\sigma_T}

And replacing we got this:

P(T

6 0
2 years ago
Consider a disease whose presence can be identified by carrying out a blood test. Let p denote the probability that a randomly s
kifflom [539]

Answer:

The expected number of tests, E(X) = 6.00

Step-by-step explanation:

Let us denote the number of tests required by X.

In the case of 5 individuals, the possible value of x are 1, if no one has the disease, and 6, if at least one person has the disease.

To find the probability that no one has the disease, we will consider the fact that the selection is independent. Thus, only one test is necessary.

Case 1: P(X=1) = [P (not infected)]⁵

                       = (0.15 - 0.1)⁵

            P(X=1) = 3.125*10⁻⁷

Case 2: P(X=6) = 1- P(X=1)

                        = 1 - (1 - 0.1)⁵

               P(X=6) = (1 - 3.125*10⁻⁷) = 0.999999

               P(X=6) = 1.0

We can then use the previously determined values to compute the expected number of tests.

E(X) = ∑x.P(X=x)

      = (1).(3.125*10⁻⁷) + 6.(1.0)

 E(X)  =  E(X) = 6.00

Therefore, the expected number of tests, E(X) = 6.00

3 0
2 years ago
Which model shows 64−−√3=4 ?
Kipish [7]

Answer:

Step-by-step explanation:

model C

7 0
2 years ago
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