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2 years ago

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In a school election, 3/4 of the students vote. There are 1464 ballots. Write and solve and equation to find the number of stude

nts.

1 answer:

erik [133]2 years ago

7 0

x = total number of students

equation is:

(3/4)x = 1464

to solve for x divide both sides by 3/4

x = 1464 / 3/4 = 1952

x = 1952

there are 1952 total students

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The graph below represents the distance a pilot is from the home airport during a period of time. A graph titled Pilot's Distanc

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Quadrilateral QRST is similar to quadrilateral EDGF. What's the scale factor from EDGF to QRST

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C. $\frac{6}{5}$

Step-by-step explanation:

The ratio of the corresponding sides of a polygon is said to be equal. The ratio gives us the scale factor.

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2 years ago

At barlow school ,4/9 of the 873 students are boys

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An online article about an opinion poll says that "41% of Americans own a gun." The poll is based on online survey interviews wi

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Answer:

See below

Step-by-step explanation:

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B) The sampling used is, as said in the statement, a randome sampling.

C) Yes! There could be a bias because of the exclusion of New England States if the people who lives there tends to have more guns than the average american population. This could be, for example, due to that those states have the least gun owning in America or, contrary, if they have the highest. If Rode Island is the most violent state and has the highest gun owning rate, the results could be biased. However, we can't confirm it without seeing the data, but there is possible.

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2 years ago

Adam must fly home to city A from a business meeting in city B. One flight option flies directly to city A from B, a distance o

g100num [7]

Answer:

The value is $k =109.6 \ miles$

Step-by-step explanation:

The diagram illustrating the question is shown on the first uploaded image

From the question we are told that

The distance from city A to B is AB = 467.3 miles

The bearing from B to C is $\theta_{BC} = N 28.7E$

The bearing from B to A is $\theta_{BA} = N 60.7E$

The bearing from A to B is $\theta_{AB} = S60.7W$

The bearing from A to C is $\theta_{AC} = S79.1W$

Generally from the diagram

$\theta_A = 180 - 60.7 -79.1$

=> $\theta_A = 40.2 ^o$

Also

$\theta_B = 32^o$

and

$\theta_C = 180 - (\theta_A +\theta_B )$

=> $\theta_C = 180 - (40.2 + 32 )$

=> $\theta_C = 107.8 ^o$

Generally according to Sine Rule

$\frac{BC}{sin (\theta_A)} = \frac{CA}{sin (\theta_B)} =\frac{AB}{sin (\theta_C)}$

=> $\frac{BC}{sin (40.2)} = \frac{CA}{sin (32)} =\frac{467.3 }{sin (107.8)}$

So

$\frac{BC}{sin (40.2)} = \frac{467.3 }{sin (107.8)}$

=> $BC = 316.8 \ miles$

Also

$\frac{CA}{sin (32)} = \frac{467.3 }{sin (107.8)}$

$CA = 260 .1 \ miles$

Generally the additional flyer miles that Adam will receive if he takes the connecting flight rather than the direct flight is mathematically represented as

$k = [CA +BC] - AB$

=> $k = [260 .1 +316.8]- 467.3$

=> $k =109.6 \ miles$

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2 years ago