Let us say weight of Javier is x pounds.
Weight of his bother = 80 pounds
Javier is 175 % or 1.75 times heavier than his brother.
So Javier's weight = x pounds= 1.75 *80 = 140 pounds.
Answer: Javier's weight is 140 pounds.
(a) Data with the eight day's measurement.
Raw data: [60,58,64,64,68,50,57,82],
Sorted data: [50,57,58,60,64,64,68,82]
Sample size = 8 (even)
mean = 62.875
median = (60+64)/2 = 62
1st quartile = (57+58)/2 = 57.5
3rd quartile = (64+68)/2 = 66
IQR = 66 - 57.5 = 8.5
(b) Data without the eight day's measurement.
Raw data: [60,58,64,64,68,50,57]
Sorted data: [50,57,58,60,64,64,68]
Sample size = 7 (odd)
mean = 60.143
median = 60
1st quartile = 57
3rd quartile = 64
IQR = 64 -57 = 7
Answers:
1. The average is the same with or without the 8th day's data. FALSE
2. The median is the same with or without the 8th day's data. FALSE
3. The IQR decreases when the 8th day is included. FALSE
4. The IQR increases when the 8th day is included. TRUE
5. The median is higher when the 8th day is included. TRUE
Answer:
Conclusion
There is no sufficient evidence to conclude that the mean of the home prices from Ascension parish is higher than the EBR mean
Step-by-step explanation:
From the question we are told that
The population mean for EBR is 
The sample mean for Ascension parish is 
The p-value is 
The level of significance is 
The null hypothesis is 
The alternative hypothesis is 
Here 
is the population mean for Ascension parish
From the data given values we see that
So we fail to reject the null hypothesis
So we conclude that there is no sufficient evidence to conclude that the mean of the home prices from Ascension parish is higher than the EBR mean
Answer:
The mean should be 80.5. This means the average number of test scores is 80.5. The mean absolute deviation should be 15.5. This means the average of the values are less than the mean by about 15.5.
