First, 123 - 55 = 68 which is how many boys voted. So, the ratio is 55:68
P(82 - q < x < 82 + q) = 0.44
P(x < 82 + q) - P(82 - q) = 0.44
P(z < (82 + q - 82)/7.4 - P(z < (82 - q - 82)/7.4) = 0.44
P(z < q/7.4) - P(z < -q/7.4) = 0.44
P(z < q/7.4) - (1 - P(z < q/7.4) = 0.44
P(z < q/7.4) - 1 + P(z < q/7.4) = 0.44
2P(z < q/7.4) - 1 = 0.44
2P(z < q/7.4) = 1.44
P(z < q/7.4) = 0.72
P(z < q/7.4) = P(z < 0.583)
q/7.4 = 0.583
q = 0.583 x 7.4 = 4.31
What is the question?
I'm assuming it is to find the length and width.
+_= plus or minus
(X+36)
____________
| |
(X) | |
|____________|
X^2+36X-2040<0
X<-36+_(36^2-4*-2040)^(1/2)
-----------------------------------
2
X<-18+_2((591)^(1/2))
This is probably not what you wanted, sorry
Leanora is factoring in Amacher the factors of the thermometer are shown in the elevator 3+3 = 7 4+4 equalsTake away 100 and then +3 that gives you 6 billion in 2/3+6+4+3+8+9 that gives you a BCDEFGHIJK jelly jelly jelly diaper
The difference in the mean rainfall is given by 19.7 - 19.3 = 0.5
The difference in the <span>mean rainfall is approximately 0.5/4.6 = 0.087 = 8.7 percent of the mean absolute deviation for last week and is 0.5/5.2 = 0.077 = 7.7 percent of the mean absolute deviation for this week.
Therefore, the difference in the </span><span>mean rainfall is approximately what percent of the mean absolute deviation 8% of the mean absolute deviation of the data sets.</span>
