<u>Complete Question:
</u>
The table (in figure) represents the recommended exercise intensity for the aerobic program based on the number of visits since the beginning program recommends a consistent intensity for three visits increase in intensity over three visits then decreasing intensity for three visits before restoring the pattern which set of values could be the intensity of embers exercise during the fourth fifth and six visits check all that apply
A.63%,63%,63%
B.66%,69%,72%
C.66%,62%,58%
D67%,67%,67%
E.63%,65%,67%
F.67%,72%,77%
<u>Answer:
</u>
<u>The following set of values could be the intensity of embers exercise during the fourth fifth and six visits
:</u>
- 66%, 69%, 72%
- 63%, 65%, 67%
- 67%, 72%, 77%
<u>
Step-by-step explanation:</u>
Given that intensity for first three visits on Amber's exercise in consistent way at the program beginning. Then it increases for 3 visits and decreases over 3 visits. In question, they asked us to find the intensity of Amber’s exercise for fourth, fifth and sixth alone.
As per given statement, first three visits are consistent in intensity (constant for visit 1, 2, 3).Then increases in intensity of Amber’s exercise for visits 4, 5, 6 (suits option B, E, F). Then it gets decreased for further visits (7, 8, 9).
Selling price of app per user = $10 per month
Total no. of user in first month = 10
To tal no. of user added per month = 7
We have to find how much money is earned in one year
So the formula is n/2 * (2a +(n-1)d)
Here we have n = 12 which is total no. of months
a = 100 , which is money earned in one month
d = 70 , which is increase in money earned per month
So money earned in a year comes out to be 5820
Answer:
a) From the chart crated with Microsoft Excel, we have that the correlation coefficient, r = √0.8581 ≈ 0.93 to the nearest hundredth
The steps used includes
1) Inputting the given data into the cells on a Microsoft Excel spread sheet
2) Highlighting and sorting the data in the cells in order of increasing Rainfall
3) Generating a dot plot using the sorted data from above
4) Adding the trend line, Square of the linear regression, and the trend line equation
5) Adding the axis labels
(b) The correlation coefficient states that there is a strong positive correlation between the monthly rainfall and and Umbrella sales
Step-by-step explanation:
<span>1. </span>When given a raw score, it must be converted
into a z-score (standard score). Raw scores cannot be placed on a normal
distribution curve because they do not have the same means and standard
deviations, but when it is converted into a z-score, the number of standard
deviations above or below the population mean can be measured. The z-scores on
the center are average, the scores on the left are lower than average and the
scores on the right are higher than average.
<span>2. </span>A z-score is a standard score which can be
placed on a normal distribution curve. A z-score indicates the distance of the
standard deviations from the mean (center of the curve).
Answer:
y2 = C1xe^(4x)
Step-by-step explanation:
Given that y1 = e^(4x) is a solution to the differential equation
y'' - 8y' + 16y = 0
We want to find the second solution y2 of the equation using the method of reduction of order.
Let
y2 = uy1
Because y2 is a solution to the differential equation, it satisfies
y2'' - 8y2' + 16y2 = 0
y2 = ue^(4x)
y2' = u'e^(4x) + 4ue^(4x)
y2'' = u''e^(4x) + 4u'e^(4x) + 4u'e^(4x) + 16ue^(4x)
= u''e^(4x) + 8u'e^(4x) + 16ue^(4x)
Using these,
y2'' - 8y2' + 16y2 =
[u''e^(4x) + 8u'e^(4x) + 16ue^(4x)] - 8[u'e^(4x) + 4ue^(4x)] + 16ue^(4x) = 0
u''e^(4x) = 0
Let w = u', then w' = u''
w'e^(4x) = 0
w' = 0
Integrating this, we have
w = C1
But w = u'
u' = C1
Integrating again, we have
u = C1x
But y2 = ue^(4x)
y2 = C1xe^(4x)
And this is the second solution