<span>(2n + 2)(2n – 2)
= (2n)^2 -2^2
= 4n^2 - 4
hope it helps</span>
Answer:
3400 m2
Step-by-step explanation:
Incomple question. However, here's the remaining part of the question:
14
2009
Meadow Fritillary= 5
Variegated Fritillary= 7
Zebra Swallowtail= 33
Eastern-Tailed Blue= 242
Louden County Butterfly Count
2010
Meadow Fritillary 34
Variegated Fritillary 95
Zebra Swallowtail 21
Eastern-Tailed Blue 168
2011
Meadow Fritillary
Variegated Fritillary
Zebra Swallowtail
Eastern-Tailed Blue
10
170
<u>Options</u>:
A) All butterfly populations are steadily decreasing.
B)All butterfly populations were larger than usual in 2010.
C)The Eastern-Tailed Blue butterfly is more common than the others.
D)The Meadow Fritillary is equally common as the Variegated Fritillary
Answer:
<u>C</u>
Step-by-step explanation:
Looking through the above count data by Louden County Wildlife Conservancy from 2009 to 2011 we notice the Eastern- Trailed Blue butterfly has a higher count, which implies that the Eastern-Tailed Blue butterfly is more common than the other butterflies.
Therefore, we could infer from the samples, that the Eastern-Tailed Blue butterfly is more common than others from the records of the past 3 three years.
Approximately 1718 have a score within that range.
We calculate the z-score for each end of this spectrum:
z = (X-μ)/σ = (2.5-3.1)/0.3 = -0.6/0.3 = -2
Using a z-table (http://www.z-table.com) we see that the area to the left of, less than, this z-score is 0.0228.
For the upper end:
z = (3.7-3.1)/0.3 = 0.6/0.3 = 2
Using a z-table, we see that the area to the left of, less than, this z-score is 0.9772.
The probability between these is given by subtracting these:
0.9772 - 0.0228 = 0.9544.
This means the proportion of people that should fall between these is 0.9544:
0.9544*1800 = 1717.92 ≈ 1718
