Rafael took 4 pumpkin pies to a family gathering.If he divides each pie into six equal-size slices,haw many slices can he serve

Sameera predicted that she would sell 38 blankets, but she actually sold 28 blankets. Which expression would find the percent er

antoniya [11.8K]

Solution: We are given:

Predicted Sales by Sameera $=38$

Actual Sales by Sameera $=28$

Now to find the Percent error, we have to use the below formula:

$Percent-Error= \frac{|Predicted-value - Actual-value|}{Actual-value} \times 100 \%$

$=\frac{|38-28|}{28} \times 100 \%$

$=\frac{10}{28}\times 100 \%$

$=35.71 \%$

Therefore, the percent error is $35.71 \%$

8 0

2 years ago

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Kiersten runs a website that helps people learn programming. Every month, Kiersten receives a subscription fee of \$10$10dollar

bogdanovich [222]

Answer:

sorry but it is wrong the answer is 1,200

Step-by-step explanation:

8 0

2 years ago

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A torch and a battery cost £2.50 altogether. The torch costs £2.00 more than the battery.

Genrish500 [490]

Answer:

$\frac{1}{10}$

Step-by-step explanation:

Let $t$ represent the cost of the torch and $b$ represent the cost of the battery.

The torch and a battery cost £2.50 altogether.

$\Rightarrow t+b=2.50$

The torch costs £2.00 more than the battery.

$\Rightarrow t=b+2.00$

We substitute the second equation into the first equation to get;

$\Rightarrow b+2.00+b=2.50$

$\Rightarrow 2b=2.50-2.00$

£2.50

$\Rightarrow 2b=0.50$

$\Rightarrow b=0.25$

The price of the battery is £0.25

We express this as a fraction of the total cost which is £2.50 to get;

$\frac{0.25}{2.5}=\frac{1}{10}$

8 0

2 years ago

Round 7905.68466806 to the nearest thousand.

mixas84 [53]

Answer:

8000 to the nearest thousand

7905.685 to the thousandth

Step-by-step explanation:

8 0

2 years ago

A manufacturer produces light bulbs that have a mean life of at least 500 hours when the production process is working properly.

denpristay [2]

Answer:

We conclude that the population mean light bulb life is at least 500 hours at the significance level of 0.01.

Step-by-step explanation:

We are given that a manufacturer produces light bulbs that have a mean life of at least 500 hours when the production process is working properly. The population standard deviation is 50 hours and the light bulb life is normally distributed.

You select a sample of 100 light bulbs and find mean bulb life is 490 hours.

Let $\mu$ = population mean light bulb life.

So, Null Hypothesis, $H_0$ : $\mu \geq$ 500 hours {means that the population mean light bulb life is at least 500 hours}

Alternate Hypothesis, $H_A$ : $\mu$ < 500 hours {means that the population mean light bulb life is below 500 hours}

The test statistics that would be used here One-sample z test statistics as we know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean bulb life = 490 hours

σ = population standard deviation = 50 hours

n = sample of light bulbs = 100

So, the test statistics = $\frac{490-500}{\frac{50}{\sqrt{100} } }$

= -2

The value of z test statistics is -2.

Now, at 0.01 significance level the z table gives critical value of -2.33 for left-tailed test.

Since our test statistic is higher than the critical value of z as -2 > -2.33, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the population mean light bulb life is at least 500 hours.

7 0

2 years ago