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OleMash [197]
1 year ago
9

باستعمال log4 2=0.5 فإن قيمة log4 32 هي

Mathematics
1 answer:
11Alexandr11 [23.1K]1 year ago
7 0

Answer:

\mathbf{\log_432}=2.5

Step-by-step explanation:

\log_42=0.5

حن بحاجة إلى إيجاد\log_432

دع\log_432=x

\log_42\times 2\times 2\times 2\times 2=x

\Rightarrow x=\log_42^5

\Rightarrow x=5\log_42   [\because \log_ab^x=x\log_ab]

\Rightarrow x=5\times0.5

\Rightarrow x=2.5

\mathbf{\therefore\log_432=2.5}

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A jar contains black marbles and green marbles. Sixty percent of the marbles in the jar are green. A number generator simulates
grigory [225]

Answer: D

Step-by-step explanation:

The number generator is not fair, in most of the experiments, considerably less than 60 % of the selected marbles are green.

And if Sixty percent of the marbles in the jar are green. A number generator should simulates randomly by selecting atleast one of the 60% of green marbles from the jar

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1 year ago
J.J.Bean sells a wide variety of outdoor equipment and clothing. The company sells both through mail order and via the internet.
melamori03 [73]

Answer:

99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

Step-by-step explanation:

We are given that a random sample of 16 sales receipts for mail-order sales results in a mean sale amount of $74.50 with a standard deviation of $17.25.

A random sample of 9 sales receipts for internet sales results in a mean sale amount of $84.40 with a standard deviation of $21.25.

The pivotal quantity that will be used for constructing 99% confidence interval for true mean difference is given by;

                      P.Q.  =  \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }  ~ t__n_1_+_n_2_-_2

where, \bar X_1 = sample mean for mail-order sales = $74.50

\bar X_2 = sample mean for internet sales = $84.40

s_1 = sample standard deviation for mail-order purchases = $17.25

s_2 = sample standard deviation for internet purchases = $21.25

n_1 = sample of sales receipts for mail-order purchases = 16

n_2 = sample of sales receipts for internet purchases = 9

Also,  s_p =\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }  =  \sqrt{\frac{(16-1)\times 17.25^{2}+(9-1)\times 21.25^{2} }{16+9-2} } = 18.74

The true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is represented by (\mu_1-\mu_2).

Now, 99% confidence interval for (\mu_1-\mu_2) is given by;

             = (\bar X_1-\bar X_2) \pm t_(_\frac{\alpha}{2}_)  \times s_p \times \sqrt{\frac{1}{n_1} +\frac{1}{n_2}}

Here, the critical value of t at 0.5% level of significance and 23 degrees of freedom is given as 2.807.

          = (74.50-84.40) \pm (2.807  \times 18.74 \times \sqrt{\frac{1}{16} +\frac{1}{9}})

          = [$-31.82 , $12.02]

Hence, 99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

5 0
1 year ago
Anthony is informed that there is a 10% chance that he will be hired by the prestigious Acme corporation. He believes that, give
Korolek [52]

Answer:

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Step-by-step explanation:

We have these following probabilities:

10% probability that he is hired by the corporation.

If he is hired by the corporation, an 80% probability that he will earn a spot on the golf team.

Given this information we can estimate that the likelihood that Anthony will soon be playing on the Acme golf team to be:

80% of 10%

So

P = 0.8*0.1 = 0.08

8% probability that Anthony will soon be playing on the Acme golf team

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Marat540 [252]

Answer:

Consider the function f (x) = (x +4) (x + 2).

Step-by-step explanation:

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1 year ago
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DochEvi [55]

Answer:

Bruce's tile covers up more space.

Step-by-step explanation:

So as we know, Bruce covers up around 1/4 of square feet and to find felicia's function we have to used the data we already have. For example, x=6 tiles, y=1 sq ft and x=12 tiles, y=2 sq ft, then we set y=kx which then we can find the value of k, 1=6k, k=1/6 then y=1/6. We then test the function with x=12 and x=18, y=1/6 12=2 and y=1/6 18=3. When the function is complete, we see that Bruce's tiles cover up more space because 1/4>1/6.

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1 year ago
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