Answer:
50 miles.
Step-by-step explanation:
Edmund fills his gas tank on Monday morning an then drives ten miles total for work each day of the work week.
With a full tank of gas he can drive 100 miles.
Question asked:
How many miles can he drive on the weekend, before he he fills up again?
Solution:
With full tank he can drive a total distance = 100 miles
Each day of the work week, he drives = 10 miles
Total miles, he drive in whole work week (Monday - Friday) = 
<em>Now, to find that many miles he can drive on the weekend (Saturday and Sunday), we will subtract total miles, he drive in whole work week from the total distance, he can drive with full tank of gas:-</em>
100 - 50 = 50 miles.
Therefore, he can drive 50 miles on the weekend, before he he fills up again.
Answer:
grumpy is 20 happy is 80
Step-by-step explanation:
<span>Given:
75% of the five-star football recruits in the nation go to universities in the three most competitive athletic conferences. </span>→ 25% goes to other schools.
<span>
five-star recruits get full football scholarships 93% of the time, regardless of which conference they go to. </span>→ 7% of the 5-star recruits don't get full football scholarships.<span>
a. The probability that a randomly selected five-star recruit who chooses one of the best three conferences will be offered a full football scholarship?
75% * 93% = 69.75%
b. What are the odds a randomly selected five-star recruit will not select a university from one of the three best conferences?
25% of selected five-star recruit will not select a university from one of the three best conferences. I got the number based on the given data. Since, 75% will go, the remaining percent won't go. Total percentage should be 100% of the population.
c. Explain whether these are independent or dependent events. Are they Inclusive or exclusive?
These are independent events. One can still go to different school and still be legible for the full football scholarship.
For question 2, pls. see attachment.</span>
Answer:
I think it would be the 2 bathchrs go by div and turn to a simple form and then overdue it by its times and calculate I hope it helps you I'm very sorry if it doesn't
Answer:
The probability that a randomly chosen code starts with M and ends with E is 0.05 ....
Step-by-step explanation:
According to the given statement we have to make five letter code from A, F, E, R, and M without repeating any letter. We have to find that what is probability that a randomly chosen code starts with M and ends with E.
Thus the probability of picking the first letter M = 1/5
After that we require the sequence (not E, not E, not E) which is equal to:
= 3/4 * 2/3* *1/2
= 1/4
Now multiply 1/5 and 1/4
1/5 * 1/4
= 1/20
= 0.05
Therefore the probability that a randomly chosen code starts with M and ends with E is 0.05 ....
