Talia is packing a moving box. She has a square-framed poster with an area of 4 square feet. The cube-shaped box has a volume of
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Answer:
Given: A triangle ABC and a line DE parallel to BC.
To prove: A line parallel to one side of a triangle divides the other two sides proportionally.
Proof: Consider ΔABC and DE be the line parallel to Bc, then from ΔABC and ΔADE, we have
∠A=∠A (Common)
∠ADE=∠ABC (Corresponding angles)
Thus, by AA similarity, ΔABC is similar to ΔADE, therefore
AB/AD= AC/AE
⇒AD+DB/AD = AE+EC/AE
⇒1+DB/AD = 1+ EC/AE
⇒DB/AD = EC/AE
Therefore, a line parallel to one side of a triangle divides the other two sides proportionally.
⇒Therefore Proved
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Answer:
f(0,0)=ln19
Step-by-step explanation:
is given as continuous function, so there exist
and it is equal to f(0,0).
Put x=rcosA annd y=rsinA
we know that , so we have that
So f(0,0)=ln19.