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2 years ago

you buy a house for $130,000. it appreciates 6% per year. How much is it work in 10 years? exponential growth or decay?

Mathematics

1 answer:

snow_lady [41]2 years ago

6 0

Answer:

Its worth would be $232,810 in 10 years....

Step-by-step explanation:

Let P be the price of house today

r = growth rate

n = number of years of appreciation

Then future price can be calculated as:

P*(1+r/100)^n

Plug the values in the formula

130,000(1+0.06)^10

130,000(1.06)^10

$232,810

Therefore its worth would be $232,810 in 10 years....

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The following differential equation is separable as it is of the form dP/dt = g(P)h(t).

dedylja [7]

Answer:

$P(1-P) = Ae^t$

Step-by-step explanation:

given differential equation is

$\frac{dP}{dt} =P-P^2\\\frac{dP}{dt} = g(P) h(t)\\g(P) = P-P^2\\h(t) = 1$

So this is separable

We separate as

$\frac{dP}{P-P^2} =1dt\\\frac{dP}{P(1-P)} =1dt$

Resolve into partial fractions to solve this

$dP(\frac{1}{P}+ \frac{1}{1-P} ) = 1dt\\ln P(1-P) = t+C\\P(1-P) = Ae^t$

So solution is $P(1-P) = Ae^t$

7 0

2 years ago

Find the average speed of a plane that leaves Bristol at 14.00 and lands in Rome at 17.15.The distance is 1200 miles

horrorfan [7]

It is very important to go through all the details that have been provided in the question. These information's will come in very handy while getting to the solution for the answer. Now let us concentrate on the problem in hand.
Distance between Bristol and Rome that the plane covers = 1200 miles
Starting time of the plane from Bristol = 14:00 hrs
Landing time of the plane in Rome = 17:15 hrs
Then
Total time taken by the plane to travel from Bristol to Rome = 17:15 - 14:00 hours
= 3 .15 hours
So
The average speed of the plane = 1200/3.15 miles per hour
= 380.95 miles per hour
From the above deduction we can conclude that the average speed of the plane traveling from Bristol to Rome is 380.95 miles per hour.

6 0

2 years ago

(HELP PLEASE) The cost for a company to produce x smartphones can be modeled by C(x)= 2x+35 and the company's total profit after

Juliette [100K]

This is the concept of algebra, the revenue of the smart phone sells is given by:
revenue=cost+profit
cost of producing an phone is:
C(x)=2x+35

Profit is given by the function:
P(x)=-x^2+120x-435
Thus the revenue will be:
R(x)=-x^2+120x-435+2x+35
R(x)=-x^2+122x-400
The answer is A

7 0

2 years ago

Read 2 more answers

Ignatz repeatedly rolls a fair $6$-sided die. What is the probability that he rolls his first $5$ before he rolls his second (no

n200080 [17]

Ignatz has a probability of rolling his first $5$ on a 6:1 probability.

5 0

2 years ago

Suppose that the weight of seedless watermelons is normally distributed with mean 6.1 kg. and standard deviation 1.9 kg. Let X b

horrorfan [7]

Answer:

a. $X\sim N(\mu = 6.1, \sigma = 1.9)$ b. 6.1 c. 0.6842 d. 0.4166 e. 0.1194 f. 8.5349

Step-by-step explanation:

a. The distribution of X is normal with mean 6.1 kg. and standard deviation 1.9 kg. this because X is the weight of a randomly selected seedless watermelon and we know that the set of weights of seedless watermelons is normally distributed.

b. Because for the normal distribution the mean and the median are the same, we have that the median seedless watermelong weight is 6.1 kg.

c. The z-score for a seedless watermelon weighing 7.4 kg is (7.4-6.1)/1.9 = 0.6842

d. The z-score for 6.5 kg is (6.5-6.1)/1.9 = 0.2105, and the probability we are seeking is P(Z > 0.2105) = 0.4166

e. The z-score related to 6.4 kg is $z_{1} = (6.4-6.1)/1.9 = 0.1579$ and the z-score related to 7 kg is $z_{2} = (7-6.1)/1.9 = 0.4737$ , we are seeking P(0.1579 < Z < 0.4737) = P(Z < 0.4737) - P(Z < 0.1579) = 0.6821 - 0.5627 = 0.1194

f. The 90th percentile for the standard normal distribution is 1.2815, therefore, the 90th percentile for the given distribution is 6.1 + (1.2815)(1.9) = 8.5349

7 0

2 years ago