Answer:
(a) 0.0833 or 8.33%
(b) 0.40 or 40%
Step-by-step explanation:
Parts line one (n1) = 1,000 parts
Defects line one (d1) = 100 parts
Parts line two (n2) = 2,000 parts
Defects line two (d2) = 150 parts
Total number of parts (n) = 3,000 parts
a. Probability of a randomly selected part being defective:
The probability is 0.0833 or 8.33%
b. Probability of a part being produced by line one, given that it is defective:
The probability is 0.40 or 40%.
Hello,
I am going to remember:
y'+3y=0==>y=C*e^(-3t)
y'=C'*e^(-3t)-3C*e^(-3t)
y'+3y=C'*e^(-3t)-3Ce^(-3t)+3C*e^(-3t)=C'*e^(-3t) = t+e^(-2t)
==>C'=(t+e^(-2t))/e^(-3t)=t*e^(3t)+e^t
==>C=e^t+t*e^(3t) /3-e^(3t)/9
==>y= (e^t+t*e^(3t)/3-e^(3t)/9)*e^(-3t)+D
==>y=e^(-2t)+t/3-1/9+D
==>y=e^(-2t)+t/3+k
Answer:
- reflection across line m
- rotation about point A'
Step-by-step explanation:
The problem statement tells you exactly what the transformations are.
The first transformation is reflection across line m.
The second transformation is rotation about point A'.
_____
These are both rigid transformations, so ΔABC ≅ A'B''C''.
Answer:
22.5%
Step-by-step explanation:
let the standard deviation for market portfolio = σₙ
Also let the standard deviation for fully diversified portfolio = σₓ
<u>To calculate fully diversified portfolio</u>
fully diversified portfolio has <em>σₓ = βσₙ</em>
From the given question beta (β) = 1.25
Also standard deviation for market portfolio (σₙ) = 18% = 0.18
<em>From the equation above, σₓ = βσₙ </em>= 1.25×0.18 = 0.225
= 22.5% (converting to percentage)
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Equation:
a = 5120
r = 1 + .2 = 1 . 2
f (n ) = 5120 * 1 . 2^n - 1
N = 4 years
f ( 4 ) 5120 * 1 . 2^4 - 1
5120 * 1 . 2^3
We want to know, The number of Highway Accidents in Four Years.
Answer: 8,847 Highway Accidents total:
Hope that helps!!!!!!!!!!! : )
