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2 years ago

You used p minutes one month on your cell phone. The next month you used 75 fewer minutes. Simplify the expression.

1 answer:

5 0

Hi there!

Let's assume that one month is represented by the variable 'm', the amount of minutes you started with is 's', and minutes you spent is 'p'.

So, one month can be represented as 'm=s-p'.

The next month is a bit more tricky. This will incorporate 75 less minutes into the equation. 'm=s-75' can be used to represent this, as we assume that you didn't use any minutes in the first month, and that p=75 in this case.

If you found this especially helpful, I'd appreciate if you'd vote me Brainliest for your answer. I want to be able to assist more users one-on-one, as well as to move up in rank! :)

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Assume there are 365 days in a year.

MissTica

Answer:

1) The probability that ten students in a class have different birthdays is 0.883.

2) The probability that among ten students in a class, at least two of them share a birthday is 0.002.

Step-by-step explanation:

Given : Assume there are 365 days in a year.

To find : 1) What is the probability that ten students in a class have different birthdays?

2) What is the probability that among ten students in a class, at least two of them share a birthday?

Solution :

$\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total number of outcome}}$

Total outcome = 365

1) Probability that ten students in a class have different birthdays is

The first student can have the birthday on any of the 365 days, the second one only 364/365 and so on...

$\frac{364}{365}\times \frac{363}{365} \times \frac{362}{365} \times \frac{361}{365}\times\frac{360}{365} \times \frac{359}{365} \times \frac{358}{365} \times \frac{357}{365} \times\frac{356}{365}=0.883$

The probability that ten students in a class have different birthdays is 0.883.

2) The probability that among ten students in a class, at least two of them share a birthday

P(2 born on same day) = 1- P( 2 not born on same day)

$\text{P(2 born on same day) }=1-[\frac{365}{365}\times \frac{364}{365}]$

$\text{P(2 born on same day) }=1-[\frac{364}{365}]$

$\text{P(2 born on same day) }=0.002$

The probability that among ten students in a class, at least two of them share a birthday is 0.002.

6 0

2 years ago

Of all the Sunny Club members in a particular city, 25% prefer swimming on weekends and 75% prefer swimming on weekdays. It is f

Ivan

P(f | weekend) = p(f & weekend)/p(weekend)
.. = 10%/25%
.. = 2/5 = 0.4

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2 years ago

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Substitute y for 10 in the equation and solve using these steps:
10=4x+2
1) Minus 2 from both sides
8=4x
2) Divide both sides by 4 (the coefficient of x)
2=x
The value of x is 2 and we can check this by substituting it back into the original equation, 10 = (4×2)+2.

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2 years ago

Melanie is making lemonade and finds a recipe that calls for 1 part lemon juice, 2 parts sugar, and 8 parts water. She juices 2

MakcuM [25]

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Mrs. Ming invested an amount of money in two accounts for one year. She invested some at 8% interest and the rest at 6% interest

Sidana [21]

0.06x+0.08 (1500-x)=106.4
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