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Gre4nikov [31]
2 years ago
6

Bill takes a vitamin B pill every 3 days and a vitamin C pill every 4 days. If he takes both pills on day 1, for how many of the

next 65 days will Bill take both pills on the same day?
Mathematics
1 answer:
e-lub [12.9K]2 years ago
8 0

Answer:

6

Step-by-step explanation:

We are given that

Bill takes a vitamin B pills every 3 days and vitamin C pill every 4 days.

We have to find how many of the next 65 days Bill will take both pills on the same day.

To find the number of days on which Bill take both pills on the same day we will find the lcm of 3 and 4.

Lcm (3,4)=3\times 4=12

Multiples of 12 lie between 1 and 65 are

12,24,36,48,60

Number of days on which Bill take both pills on the same day=5

If he takes both pills on day 1

Therefore, total number of days on which Bill take both pills on the same day=5+1=6

Hence, otal number of days on which Bill take both pills on the same day=6

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Two different samples will be taken from the same population of test scores where the population mean and standard deviation are
Alenkinab [10]

Answer:

The sample consisting of 64 data values would give a greater precision.

Step-by-step explanation:

The width of a (1 - <em>α</em>)% confidence interval for population mean μ is:

\text{Width}=2\cdot z_{\alpha/2}\cdot \frac{\sigma}{\sqrt{n}}

So, from the formula of the width of the interval it is clear that the width is inversely proportion to the sample size (<em>n</em>).

That is, as the sample size increases the interval width would decrease and as the sample size decreases the interval width would increase.

Here it is provided that two different samples will be taken from the same population of test scores and a 95% confidence interval will be constructed for each sample to estimate the population mean.

The two sample sizes are:

<em>n</em>₁ = 25

<em>n</em>₂ = 64

The 95% confidence interval constructed using the sample of 64 values will have a smaller width than the the one constructed using the sample of 25 values.

Width for n = 25:

\text{Width}=2\cdot z_{\alpha/2}\cdot \frac{\sigma}{\sqrt{25}}=\frac{1}{5}\cdot [2\cdot z_{\alpha/2}\cdot \sigma]        

Width for n = 64:

\text{Width}=2\cdot z_{\alpha/2}\cdot \frac{\sigma}{\sqrt{64}}=\frac{1}{8}\cdot [2\cdot z_{\alpha/2}\cdot \sigma]

Thus, the sample consisting of 64 data values would give a greater precision

5 0
1 year ago
Read 2 more answers
A 0.143-Henry Inductor is connected in series with a variable resistor to a 208-volt 400-cycle source. For what value of capacit
aleksandr82 [10.1K]

Answer:

A.)359.2, B.)2.5 uf

Step-by-step explanation:

E / I = R

208 / 1.04 = 200 ohms

2*pi*f*L = Xl

6.28*400*.143 = 359.2 ohm

1 / (2*pi*f*Xc) = c

1 /(6.28*400*159.2) = 2.5 uf

8 0
2 years ago
A cement bridge post is 24 inches square and 15 feet 9 inches in length. If the cement weighs 145 pounds per cubic foot, how muc
lisov135 [29]

Answer:

The answer is option (C), One cement bridge post weighs 9,135 pounds

Step-by-step explanation:

Step 1: Get the total volume of a cement bridge post

The cement bridge post is in the shape of a cuboid, therefor the volume of the cement bridge post can be expressed as;

Volume of cement bridge post=Base area×Length

where;

Base area=(24^2) inches square

1 foot=12 inches

Convert 24 inches to foot=24/12=2^2=4 feet²

Length=15 feet and 9 inches

1 foot=12 inches

Convert 9 inches to foot=9/12=0.75 feet

Total length=(15+0.75)=15.75 feet

replacing;

Volume of cement bridge post=(4×15.75)=63 cubic feet

Volume of cement bridge post=63 cubic feet

Step 2: Get the total weight of the cement bridge post

Total weight of the cement bridge post=Weight per cubic foot×total volume of the cement bridge post

where;

Weight per cubic foot=145 pounds per cubic foot

Total volume of the cement bridge post=63 cubic feet

replacing;

Total weight of the cement bridge post=(145×63)=9,135 pounds

One cement bridge post weighs 9,135 pounds

8 0
1 year ago
Edmund fills his gas tank on Monday morning an then drives ten miles total for work each day of the work week. With a full tank
timama [110]

Answer:

50 miles.

Step-by-step explanation:

Edmund fills his gas tank on Monday morning an then drives ten miles total for work each day of the work week.

With a full tank of gas he can drive 100 miles.

Question asked:

How many miles can he drive on the weekend, before he he fills up again?

Solution:

With full tank he can drive a total distance = 100 miles

Each day of the work week, he drives = 10 miles

Total miles, he drive in whole work week (Monday - Friday) = 10\times5=50\ miles

<em>Now, to find that many miles he can drive on the weekend (Saturday and Sunday), we will subtract total miles, he drive in whole work week from the total distance, he can drive with full tank of gas:-</em>

100 - 50 = 50 miles.

Therefore, he can drive 50 miles on the weekend, before he he fills up again.

4 0
2 years ago
For her vacation Mrs. Andrews bought $300 worth of traveler's checks in $10 and $20 denominations
Nookie1986 [14]

Option C

The expression 20(22 - x) represents the value of the $20  traveler's checks she has.

<u>Solution:</u>

Given, For her vacation Mrs. Andrews bought $300 worth of traveler's checks in $10 and $20 denominations travelers checks in all,  

We have to find how many of each denomination does she have?

Let x represent the number of $10 traveler's checks she has,

Then, $10(x) + $20(number of $20 checks) = 300

10x + 20($20 checks) = 300

x + 2(number of $20 checks) = 30 ⇒ (1)

Now let us see the given options, for value of $20 checks,

It should be in format, that, $20 x number of $20 checks  

⇒ 20(total checks - $10 checks) ⇒ 20(total checks – x), as we can see only C is in that format, it is correct and total number of checks = 22.

Then, (1) ⇒ x + 2(22 – x) = 30

⇒ x + 44 – 2x = 30

⇒2x – x = 44 – 30

⇒ x = 14

So, $10 checks count = 14, then, $20 checks count = 22 – 14 = 8.

Hence, there are 14 $10 checks and 8 $20 checks, and option c is correct.

7 0
1 year ago
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