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Gre4nikov [31]
2 years ago
6

Bill takes a vitamin B pill every 3 days and a vitamin C pill every 4 days. If he takes both pills on day 1, for how many of the

next 65 days will Bill take both pills on the same day?
Mathematics
1 answer:
e-lub [12.9K]2 years ago
8 0

Answer:

6

Step-by-step explanation:

We are given that

Bill takes a vitamin B pills every 3 days and vitamin C pill every 4 days.

We have to find how many of the next 65 days Bill will take both pills on the same day.

To find the number of days on which Bill take both pills on the same day we will find the lcm of 3 and 4.

Lcm (3,4)=3\times 4=12

Multiples of 12 lie between 1 and 65 are

12,24,36,48,60

Number of days on which Bill take both pills on the same day=5

If he takes both pills on day 1

Therefore, total number of days on which Bill take both pills on the same day=5+1=6

Hence, otal number of days on which Bill take both pills on the same day=6

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Shawna found coins worth $4.32. One-fourth of the found coins are pennies and one-sixth are quarters. The number of nickels foun
Sunny_sXe [5.5K]

Answer:

8 quarters

12 nickels

12 pennies

16 dimes

Step-by-step explanation:

Let the number of coins = x

One-fourth of the found coins are pennies ⇒ 0.25 x

one-sixth are quarters ⇒ (1/6) x

The number of nickels found is 1.5 times the number of quarters⇒ 1.5*(1/6)x

Let ⇒ There no dimes.

Penny = 1 cent , quarter = 25 cents , nickel = 5 cents

$4.32 = 432 cents

So,

0.25x + (1/6) x * 25 + 1.5*(1/6)x * 5 = 432

Solve for x

(17/3) x = 432

x = 432*3/17 = 76.24

The number of coins must be integer number so, we should assume there are some of coins are dimes

Let the number of coins that is dimes = y

The number of total coins = x

So, 0.25 x + (1/6) x + 1.5 * (1/6) x + y = x

∴ y = x - (0.25 x + (1/6) x + 1.5 * (1/6) x) = (1/3) x ⇒ (1)

And the total coins worth $4.32 = 432 cents

0.25x + (1/6) x * 25 + 1.5*(1/6)x * 5 + 10 y = 432

By substitution with y from (1)

∴ 0.25x + (1/6) x * 25 + 1.5*(1/6)x * 5 + 10 * (1/3) x = 432

Solve for x, combine the terms contain x

∴ (0.25 + (1/6)*25 + 1.5*(1/6)*5 + 10 * (1/3)) x = 432

∴ 9 x = 432

∴ x = 432/9 = 48 coins

So, The number of quarters = 1/6 x = 8 quarters

The number of nickels = 1.5 number of quarters = 1.5*4 = 12 nickels

The number of pennies = 1/4 x = 12 pennies

The number of dimes = 1/3 x = 16 dimes

5 0
2 years ago
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