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2 years ago

Solve for a.

Mathematics

2 answers:

FinnZ [79.3K]2 years ago

8 0

Answer:

iii) a=3b/2

Step-by-step explanation:

7a-2b= 5a+b

7a-5a=2b+b

2a=3b

a=3b/2

pychu [463]2 years ago

8 0

Answer:

$\large\boxed{a=\dfrac{3b}{2}=\dfrac{3}{2}b=1.5b}$

Step-by-step explanation:

$7a-2b=5a+b\qquad\text{add}\ 2b\ \text{to both sides}\\\\7a-2b+2b=5a+b+2b\\\\7a=5a+3b\qquad\text{subtract}\ 5a\ \text{from both sides}\\\\7a-5a=5a-5a+3b\\\\2a=3b\qquad\text{divide both sides by 2}\\\\\dfrac{2a}{2}=\dfrac{3b}{2}\\\\a=\dfrac{3b}{2}$

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Using the ratio table the dogs weight is:

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For this case we have the following conversion:

20 pounds = 9 kilograms

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2 years ago

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A phone company charges $0.45 for the first minute and $0.35 for each additional minute for a long distance call. Which numerica

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Emilia saved nickels, dimes, and quarters in a jar. She had as many quarters as dimes, but twice as many nickels as dimes. If th

olchik [2.2K]

Let us assume number of nickels = n,

number of dimes = d and

number of quarters = q.

Total number of coins = 844.

We can setup a statement "number of nickels + number of dimes +number of quarters = Total coins.

And we can setup an equation for the above statement as

n+d+q = 844 ---------------------equation(1).

We also given: Emilia had as many quarters as dimes.

Therefore, number of quarters = number of dimes.

So, we can setup another equation as

q = d ------------------------equation(2).

Also given : "twice as many nickels as dimes".

We can setup another equation for this statement as

n = twice of number of dimes

or n= 2d -------------------------- equation (3).

We got three equations.

Let us solve system of three equation by substitution method.

Substituting q = d and n= 2d in equation (1), we got

n+d+q = 844 => 2d +d + d = 844.

Adding d's, we get

4d =844.

Dividing both sides by 4, we get

$\frac{4d}{4}=\frac{844}{4}$

d = 211.

Therefore number of dimes = 211.

Let us find number of nickels and number of quarter coins now.

We know, number of quarters = number of dimes.

Therefore, number of qurters = 221.

Total number of coins = 844.

Therefore, number of nickels = 844 - (number of quarters + number of dimes).

= 844 -(221+221) = 844 - 442

= 402.

So, the number of nickels =402.

Let us find the total values of all the coins.

A nickel = $0.05

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A quarter = $0.25.

Total value = 0.05 *(number of nickels) + 0.10*(number of dimes) + 0.25*(number of quarters).

= 0.05* 402 + 0.10 *221 + 0.25*221.

= 20.10 + 22.10 + 55.25.

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Therefore, total value of all 844 coins = $97.45.

Emilia had saved $97.45.

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