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avanturin [10]
2 years ago
6

Simplify the expression. (−5g5h6)2(g4h2)4

Mathematics
2 answers:
Tanzania [10]2 years ago
7 0
= 25*g^10 h^12 * g^16 h^8

= 25 g^26 h^20
Colt1911 [192]2 years ago
4 0

We have to simplify the expression here. The expression given,

(-5g^5h^6)^2(g^4h^2)^4

Now to find (-5g^5h^6)^2 we will use power of a product property. We have to distribute the power here. We will get,

(-5g^5h^6)^2 = (-5)^2(g^5)^2(h^6)^2

= 25(g^5)^2(h^6)^2

Now we will use power of a power property. If given (a^m)^n we will have to multtiply the powers and we will get a^{mn}. So we will get here,

25(g^5)^2(h^6)^2 = 25 g^{10} h^{12}

Now the next part is (g^4h^2)^4

By using power of a power property we will get,

(g^4)^4(h^2)^4 = g^{16}h^8

Now we have to multiply them.

(25g^{10}h^{12}  )(g^{16}h^8)

Now we have to use product of powers property. If we have same base them we will have to add the exponents there. The formula is (a^m)(a^n) = a^{(m+n)}. So we will get here,

25(g^{10} g^{16})(h^{12}  h^{8})

25g^{(10+16)} h^{(12+8)}

25g^{26}h^{20}

So we have got the required simplified answer here.

The simplified answer is 25g^{26}h^{20}.

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A stuntman jumping off a 20-m-high building is modeled by the equation h = 20 – 5t2, where t is the time in seconds. A high-speed camera is ready to film him between 15 m and 10 m above the ground. For which interval of time should the camera film him?

Answer:

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Step-by-step explanation:

Given:

A stuntman jumping off a 20-m-high building is modeled by the equation

h =20-5t^{2}-----------(1)

A high-speed camera is ready to making film between 15 m and 10 m above the ground

when the stuntman is 15m above the ground.

height h = 15m  

Put height value in equation 1

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5t^{2} =5

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