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KengaRu [80]
2 years ago
11

hannah and her family want to hike 8 miles per day along a 125 mile-long trail.How many days will hannah and her family hike exa

ctly 8 miles
Mathematics
2 answers:
Scorpion4ik [409]2 years ago
6 0
Do 125÷8 and that's your answer your welcome
adoni [48]2 years ago
5 0
15 days in exactly 8 miles
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kirza4 [7]
Answer: $2.26
10% of $52.50 is 5.25. Then, $52.50-$5.25 is $47.25. $49.99-$47.25 is $2.26
4 0
2 years ago
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Alexeev081 [22]

<em>so</em><em> </em><em>the</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>3</em><em>6</em><em>.</em>

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7 0
2 years ago
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7 divided by 423 full answer
anygoal [31]
The answer is 0.01654846336
3 0
2 years ago
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A sample of 1714 cultures from individuals in Florida diagnosed with a strep infection was tested for resistance to the antibiot
Damm [24]

Answer:

a) p represent the real population proportion of people who showed partial or complete resistance to the antibiotic

b) \hat p=\frac{973}{1714}=0.568 represent the estimated proportion of people who showed partial or complete resistance to the antibiotic

c) We are confident (95%) that the true proportion of individuals in Florida diagnosed with a strep infection was tested for resistance to the antibiotic penicillin present partial or complete resistance to the antibiotic is between 54.5% to 59.1%.  

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Part a

Description in words of the parameter p

p represent the real population proportion of people who showed partial or complete resistance to the antibiotic

\hat p represent the estimated proportion of people who showed partial or complete resistance to the antibiotic

n=1714 is the sample size required

z_{\alpha/2} represent the critical value for the margin of error

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Part b

Numerical estimate for p

In order to estimate a proportion we use this formula:

\hat p =\frac{X}{n} where X represent the number of people with a characteristic and n the total sample size selected.

\hat p=\frac{973}{1714}=0.568 represent the estimated proportion of people who showed partial or complete resistance to the antibiotic

Part c

The confidence interval for a proportion is given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 95% confidence interval the value of \alpha=1-0.95=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=1.96

And replacing into the confidence interval formula we got:

0.568 - 1.96 \sqrt{\frac{0.568(1-0.568)}{1714}}=0.545

0.568 + 1.96 \sqrt{\frac{0.56(1-0.56)}{1714}}=0.591

And the 95% confidence interval would be given (0.545;0.591).

We are confident that about 54.5% to 59.1% of individuals in Florida diagnosed with a strep infection was tested for resistance to the antibiotic penicillin present partial or complete resistance to the antibiotic.  

5 0
2 years ago
Which of the following are steps in multiplying fractions? Multiply the numerators. Divide the numerator by the denominator. Mul
aksik [14]
You times the numerator by the numerator and the denominator by the denominator
thats all
8 0
2 years ago
Read 2 more answers
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