Answer:
A. Because the measure of the angle 
is 
and the angles and 
are Vertical angles. Therefore, they are congruent ( 
)
B. 
Step-by-step explanation:
<h3> <em><u>The missing figure is attached.</u></em></h3><h3 />
You can observe in the figure that the parallel lines 
and 
are intersected by a another line 
(this is a transversal).
Let's begin with PART B:
Observe that the angles 
and are located inside the parallel lines and they alternate sides of the transversal. Therefore, we can determine that these angles are "Alternate Interior Angles".
Since the lines and are parallel, we know that the Alternate Interior Angles are congruent. Then:
Now we can solve the PART A.
Observe the figure.
Since the angle and the angle share the same vertex, they are "Vertical angles" and, therefore, they are congruent:
Answer: 
Step-by-step explanation:
According to the given information, we have
Sample size : n= 50
Since population standard deviation is unknown, so we use t-test.
Critical value for 95 percent confidence interval :
Confidence interval : 
Required 95% confidence interval :
<em><u>Answer:</u></em>
1/2
1/3
6
1/6
<em><u>Step-by-step explanation:</u></em>
When we are finding the opposite of a scale factor, the scale factor is always the reciprocal. E.g. From S to R, the scale factor is 3, so from R to S, the scale factor is 1/3 so:
1. From T to S, it's the reciprocal of the scale factor (2) so 1/2
2. From S to R, it's the reciprocal of the scale factor (3) so 1/3
3. From R to T, is the from a figure to a figure to a figure so we can multiply the two scale factors (2 and 3) to get 6
4. From T to R, that's the opposite of R to T, so it's the reciprocal of the scale factor from R to T (6) so 1/6
This question is not complete
Complete Question
A boat sails 4km on a bearing of 038 degree and then 5km on a bearing of 067 degree.(a)how far is the boat from its starting point.(b) calculate the bearing of the boat from its starting point
Answer:
a)8.717km
b) 54.146°
Step-by-step explanation:
(a)how far is the boat from its starting point.
We solve this question using resultant vectors
= (Rcos θ, Rsinθ + Rcos θ, Rsinθ)
Where
Rcos θ = x
Rsinθ = y
= (4cos38,4sin38) + (5cos67,5sin67)
= (3.152, 2.4626) + (1.9536, 4.6025)
= (5.1056, 7.065)
x = 5.1056
y = 7.065
Distance = √x² + y²
= √(5.1056²+ 7.065²)
= √75.98137636
= √8.7167296826
Approximately = 8.717 km
Therefore, the boat is 8.717km its starting point.
(b)calculate the bearing of the boat from its starting point.
The bearing of the boat is calculated using
tan θ = y/x
tan θ = 7.065/5.1056
θ = arc tan (7.065/5.1056)
= 54.145828196°
θ ≈ 54.146°
Answer:
29119.66666...+14561.3333...=43681, 209ft^2, not square feet.
Step-by-step explanation:
<em>"One side of a rectangle is 3 feet shorter than twice the other side find the sides if the area is 209 feet squared"</em>
Ok, so this is a tricky one- <em> 209 feet squared, </em>not 209 square feet, therefore the area is 209^2, or 43,681.
Next, let's define our variables-
<em>x= the "other side"</em>
<em>z= 3 feet shorter than twice side</em>
We can now make these (useful) equations
z=2x-3
43681= (2x-3)+x
We will focus on the latter for now-
Simplify
43681= (2x-3)+x
43681= 2x-3+x
43681= 3x-3
+3
43684=3x
/3
14561.3333...=x
z=2x-3
z=2*(14561.3333)-3
z=29119.66666....
29119.66666...+14561.3333...=43681
