The mean temperature for the first 4 days in January was 1°C.

Mathematics

1 answer:

soldier1979 [14.2K]2 years ago

5 0

-4 degrees I think.

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The school play started at 2:10pm and ended at 3:22pm. How long did the play last?

Anna35 [415]

2:10=>3:10, was 1 hour
3:10=> 3:22, were 12 minutes

the play last 1 hour 12 minutes (or 60+12= 72 minutes).

3 0

2 years ago

Read 2 more answers

A 2.2 GB game is being downloaded onto your laptop. When you have downloaded half a gigabyte, you notice that your computer has

andreev551 [17]

Answer:

$0.01m +\frac{1}{2} \geq 2.2$

Step-by-step explanation:

Let m be number of minutes it will take to download the whole game.

We are told that computer is downloading at a rate of 0.01 GB per minute and half GB game is already downloaded. So 0.01*m+0.5 will be equal to 2.2 as game size is 2.2 GB.

Let us find the least number of minutes it will take to download the whole game.

$0.01m +\frac{1}{2} \geq 2.2$

$0.01m +0.5\geq 2.2$

$0.01m \geq 2.2-0.5$

$0.01m \geq 1.7$

$m\geq \frac{1.5}{0.01}$

Therefore, $0.01m +\frac{1}{2} \geq 2.2$ is our desired inequality.

6 0

2 years ago

Which hyperbola has one focus point in common with the hyperbola (y+11)^2/(15^2)-(x-7)^2/(8^2)=1

irina [24]

$\bf \textit{hyperbolas, vertical traverse axis }\\\\
\cfrac{(y-{{ k}})^2}{{{ a}}^2}-\cfrac{(x-{{ h}})^2}{{{ b}}^2}=1
\qquad 
\begin{cases}
center\ ({{ h}},{{ k}})\\
vertices\ ({{ h}}, {{ k}}\pm a)
\end{cases}\\\\
-------------------------------\\\\
\cfrac{(y+11)^2}{15^2}-\cfrac{(x-7)^2}{8^2}=1\implies \cfrac{(y-(-11))^2}{15^2}-\cfrac{(x-7)^2}{8^2}=1\\\\
-------------------------------\\\\
c=\textit{distance from the center to either foci}\\\\
c=\sqrt{a^2+b^2}\implies c=\sqrt{15^2+8^2}\implies \boxed{c=17}$

now, if you notice, the positive fraction, is the one with the "y" variable, and that simply means, the hyperbola traverse axis is over the y-axis, so it more or less looks like the picture below.

now, from the hyperbola form, we can see the center is at (7, -11), and that the "c" distance is 17.

so, from -11 over the y-axis, we move Up and Down 17 units to get the foci, which will put them at (7, -11-17) or (7, -28) and (7 , -11+17) or (7, 6)