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gogolik [260]
2 years ago
11

Simon took out a zero-interest loan for $3,300 to buy a boat. He must pay $300 per month to pay off the total balance of the boa

t's purchase price. Simon also has $1,000 in his savings account. He plans to deposit $600 every month in this account. So, Simon would like a system of equations that tells him at what point he will be able to pay off the total balance for the boat with the help of his savings. Write the second equation in the system. Enter the correct answer in the box. Substitute numerical values into the expression for all known variables.
Mathematics
2 answers:
trasher [3.6K]2 years ago
5 0

Answer:

y equals 300x plus 3300

Step-by-step explanation:

Andru [333]2 years ago
4 0

Answer:

After 3 months, Simon will be able to pay off his loan with the money he holds at his savings account.

Step-by-step explanation:

ending loan's principal balance = beginning loan's principal balance - number of months x $300

or we can simplify it:           l₁ = l₀ - 300x ⇒ l₁ = 3,300 - 300x

l₁ = ending loan's principal balance

x = number of months

ending savings account balance = beginning savings account balance + number of months x $600

or we can simplify it:         s₁ = s₀ + 600x ⇒  s₁ = 1,000 + 600x

s₁ = ending savings account balance

x = number of months

account balances for months

                                    month 1        month 2         month 3         month 4

boat loan                     $3.000         $2,700          $2,400           $2,100

savings account          $1,600         $2,200          $2,800           $3,400

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yawa3891 [41]

Answer: 8


Step-by-step explanation:

Given: Pedro cut a sheet of poster board into 10 equal parts.

let x be the total sheet.

then, one part of sheet= \frac{1}{10} of the sheet

Now, His brother used some of the poster board and now 8/10 is left.

Therefore, if Pedro wants to make a sign from  each remaining part of the poster board.

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2 years ago
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Varvara68 [4.7K]

Answer:

a) P = 0.039

b) The expected number of days is 10 days.

Step-by-step explanation:

The most appropiate distribution to use in this case is the geometric distribution, in order to calculate the probability of a success after k failure trials.

The probability of success, as each of the 10 products are assumed to have fair probabilities, is:

p=1/10=0.1

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a) The probability that exactly this product is selected exactly 10 days from now is the probability that is not selected (probbility q) for the next 9 days and selected (probability p) at the 10th day:

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Answer:

V(t) = 25000 * (0.815)^t

The depreciation from year 3 to year 4 was $2503.71

Step-by-step explanation:

We can model V(t) as an exponencial function:

V(t) = Vo * (1+r)^t

Where Vo is the inicial value of the car, r is the depreciation rate and t is the amount of years.

We have that Vo = 25000, r = -18.5% = -0.185, so:

V(t) = 25000 * (1-0.185)^t

V(t) = 25000 * (0.815)^t

In year 3, we have:

V(3) = 25000 * (0.815)^3 = 13533.58

In year 4, we have:

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The depreciation from year 3 to year 4 was:

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BlackZzzverrR [31]

Answer: Arnav is 1.8m

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