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schepotkina [342]
2 years ago
13

Three judges measure the lap times of a runner and each measurement is different from the others by a few hundredths of a second

. The most likely reason for this difference is
Mathematics
1 answer:
ohaa [14]2 years ago
6 0

Answer:

Systematic error

Step-by-step explanation:

Assuming that none of the judges are biased, the most likely reason for this difference is the occurrence of systematic errors.

Systematic errors are errors introduced by inaccuracy in the experimental design, be it in the observation or measurement process.

In this case, the reaction time from observing the finish and stopping the clock for each judge might be different, which configures a systematic error.

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Polygon YYY has an area of 111111 square units. Celia drew a scaled version of Polygon YYY using a scale factor of 333 and label
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Each cone of the hourglass has a height of 15 millimeters. The total height of the sand within the top portion of the hourglass
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Calculate the volume of sand, the cone will be completely filled and the cylinder will have sand up to the 30 mm level.

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= 1/3 * pi * (6 mm)^2 * 15
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= pi * (6 mm)^2 * 30 mm
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The total sand is the sum:
= 1080 pi cubic mm +180 pi cubic mm
= 1260 pi cubic mm. <span>
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One of the vertices of △PQR is P(2, −1). The midpoint of PQ is M(3, 0). The midpoint of QR is N(5, 3). Show that MN || PR and MN
VLD [36.1K]

Answer:

<em>See the proof below</em>

Step-by-step explanation:

Given the following coordinates

P(2, −1)

Midpoint of PQ M(3, 0)

We can get the coordinate point Q using the midpoint formula;

M(X,Y) = (x1+x2/2, y1+y2/2)

X = x1+x2/2

3 = 2+x2/2

6 = 2+x2

x2 = 6-2

x2 = 4

Y = y1+y2/2

0 = -1+y2/2

0 = -1 + y2

y2 = 0+1

y2 = 1

<em>Hence the coordinate of Q is (4, 1)</em>

Next is to get the coordinate of R

Given the midpoint of QR to be N(5, 3)

(5,3) = (4+x2/2, 1+y2/2)

5 = 4+x2/2

10 = 4+x2

x2 = 10-4

x2 = 6

1+y2/2 = 3

1+y2 = 6

y2 = 6-1

y2 = 5

<em>Hence the coordinate of R is (6,5)</em>

<em></em>

Given the coordinates M(3, 0) and N(5, 3)

Slope is expressed as:

m = y2-y1/x2-x1

m = 3-0/5-3

m = 3/2

Slope of MN = 3/2

Get the slope of PR

Given the coordinates P(2, −1) and R (6,5)

Slope of PR = 5-(-1)/6-2

Slope of PR = 5+1/4

Slope of PR = 6/4 = 3/2

<em>Since the slope of MN is equal to that of PR, hence MN is parallel to PR i.e MN || PR</em>

<em></em>

To show that MN = 1/2PR, we will have to take the distance between M and N and also P and R first as shown:

For MN with coordinates  M(3, 0) and N(5, 3)

MN = √(x2-x1)²+(y2-y1)²

MN = √(5-3)²+(3-0)²

MN = √2²+3²

MN = √13

Get the length of PR where P(2, −1) and R (6,5)

PR = √(6-2)²+(5+1)²

PR = √4²+6²

PR = √16+36

PR = √52

PR = √4*13

PR = √4*√13

PR = 2√13

Since MN = √13

PR = 2MN

Divide both sides by 2

PR/2 = 2MN/2

PR/2 = MN

Hence MN = 1/2 PR (Proved!)

8 0
1 year ago
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