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Ostrovityanka [42]
2 years ago
15

What are the possible numbers of positive real, negative real, and complex zeros of f(x) = −7x4 − 12x3 + 9x2 − 17x + 3?

Mathematics
1 answer:
madreJ [45]2 years ago
8 0
Now, recall Descartes Rule of Signs.  Check the picture below.

the +x part, gives us the positive Real zeros, and it depends on how many times the sign changes from term to term, notice in the picture, it changed 3 times, so the positive real ones are 3, or 3-2, namely 1, so 3 or 1.

the negative real ones, come from using -x as the argument on f(x), and as you can see in the picture, there was only 1 sign change, meaning the negative real zeros are only 1.

since, based on the fundamental theorem of algebra the polynomial has 4 roots at most then,

3 positive real ones, and 1 negative real one, no complex ones

or

1 positive real one, and 1 negative real one, and 2 complex ones

bear in mind that complex always come in pairs, never alone.

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Adrian Beltre hit 48 home runs during the 2004 Major League Baseball season, but only hit 19 home runs in the 2005 season. By wh
aliya0001 [1]

Answer:

60.42%

Step-by-step explanation:

Number of home runs hit by Adrian Beltre in 2004 = 48

Number of home runs hit by Adrian Beltre in 2005 = 19

To find:

Percentage decrease in home run production from 2004 to 2005.

Solution:

To find the percentage decrease, first of all we need to find the decrease in the number of home runs and then we will divide with the number of home runs in 2004 and then finally will multiply the result with 100 to get the percentage decrease.

Decrease in the number of home runs = Number of home runs in 2004 - Number of home runs in 2005 = 48 - 19 = 29

\text{Percentage of decrease in Home runs} = \dfrac{\text{Decrease in home runs}}{\text{Number of home runs in 2004}}\times 100\\\Rightarrow \text{Percentage of decrease in Home runs} = \dfrac{29}{48}\times 100 \approx \bold{60.42\%}

Therefore, by 60.42% Beltre's home run production has decreased from 2004 to 2005.

4 0
2 years ago
Sammy and Pippa's teacher gives them a homework question to solve. She tells them to plot the points A(5, -1), B(9, 4), C(15, 1)
kvv77 [185]

Answer:

Pippa

Step-by-step explanation:

A square has

  • parallel opposite sides
  • perpendicular adjacent sides
  • perpendicular diagonals

A rhombus has  

  • parallel opposite sides
  • non-perpendicular adjacent sides
  • perpendicular diagonals

Thus, we can identify the shape by comparing the slopes of the adjacent sides.

1. Draw the shape

See the graph below

2. Calculate the slope of AB

m = (y₂ - y₁)/(x₂ - x₁) = (4 - (-1))/(9 - 5) = (4 + 1)/4 = 5/4

3. Calculate the slope of BC

If BC⟂AP, its slope should be -4/5 .

m = (y₂ - y₁)/(x₂ - x₁) = (1 - 4)/(15 - 9) =-3/6 = -1/2

½ ≠ -⅘

The two lines are not perpendicular.

Pippa is right. The shape is a rhombus.

 

5 0
2 years ago
Bernita and Derek each plot a number on a number line. The numbers are unique but have the same absolute value. The sum of the a
grandymaker [24]

Answer:

<h2>The answer is 75 and 75</h2>

Step-by-step explanation:

hope this helps!!

6 0
2 years ago
Read 2 more answers
give an example on an addition problem in which you would and would not group the addends differently to add
Murrr4er [49]
Addends are any of the numbers added together in an equation. 

The only time their grouping would matter would be if there were parentheses used to alter the normal Order of Operations. 

For ex:
2 - (8 + 3)  here, the 8 and 3 have to be grouped together before doing the subtraction.

Any addition problem without parentheses can be used for one where the grouping doesn't matter
3 0
2 years ago
Below is the five Number summary for a 136 hikers who recently completed the John muir trail JMT the variable is the amount of t
Helga [31]

Answer:

IQR = Q_3 -Q_1 = 28-18 = 10

Now we can find the limits in order to determine outliers like this:

Left = Q_1 -1.5 IQR = 18 -1.5*10=3

Right = Q_1 +1.5 IQR = 18 +1.5*10=33

So for this case the left boundary would be 3, if a value is lower than 3 we consider this observation as an outlier

b. 3

Step-by-step explanation:

For this case we have the following summary:

Minimum = 9 represent the minimum value

Q_1 = 18 represent the first quartile

Median =Q_2= 21 represent the median

Q_3 = 28 represent the third quartil

Maximum=56 represent the maximum

If we use the 1.5 IQR we need to find first the interquartile range defined as:

IQR = Q_3 -Q_1 = 28-18 = 10

Now we can find the limits in order to determine outliers like this:

Left = Q_1 -1.5 IQR = 18 -1.5*10=3

Right = Q_1 +1.5 IQR = 18 +1.5*10=33

So for this case the left boundary would be 3, if a value is lower than 3 we consider this observation as an outlier

b. 3

7 0
2 years ago
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