Jennifer can run 12 miles in 2 hours, and she can bike 33 miles in 3 hours. What is Jennifer’s biking speed?
1 answer:
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Answer:
Check the explanation
Step-by-step explanation:
One way ANOVA
The null and alternative hypothesis for this one way ANOVA is given as below:
Null hypothesis: H0: There is no significant difference in the averages of the scores for the quizzes, exams and final only.
Alternative hypothesis: There is a significance difference in the averages of the scores for the quizzes, exams and final only.
The ANOVA table with calculations can be seen in the attached images below:
In the attached image below, we get the p-value for this one way ANOVA test as 0.0221. We do not reject the null hypothesis if the p-value is greater than the given level of significance and we reject the null hypothesis if the p-value is less than the given level of significance or alpha value.
In the attached image below, we are given that the p-value = 0.0221 and level of significance or alpha value = 0.05, that is p-value is less than the given level of significance. So, we reject the null hypothesis that there is no significant difference in the averages of the scores for the quizzes, exams and final only. This means we conclude that there is a significance difference in the averages of the scores for the quizzes, exams and final only.
Answer: The drive was 24.32% full when the transfer began.
Step-by-step explanation:
Given: The rate of transferring file = 4.44 megabytes per second.
After 32 seconds, the amount of data on the drive = 384 megabytes
The amount of transferred data = megabytes
Therefore, the amount of data in the drive at the beginning is given by :-
The drive had a maximum capacity of 1000 megabytes.
Hence, the drive was 24.32% full when the transfer began.
Answer:
Step-by-step explanation:
The date from the given table, is expressed as follows;
Area of Vegetable Garden (in square feet); 338, ___, 147.25, ___
Length of Tomato Patch (in feet); ___, 6.5, ___, 7
The length of the tomato patch increases with decrease in the area of the garden
Given that the length of the tomato patch is the independent variable, we can have;
Length of Tomato Patch (in feet); 6.25, 6.5, 6.75, 7
Therefore, for an increase in the length of the tomato patch from 6.25 to 6.75, (a change of Δl = 0.5) the area of the vegetable garden decreased from 338 to 147.25 which is a decrease of ΔA = 190.75
Therefore, the width of the tomato patch, w = ΔA/Δl = 190.75/0.5 = 381.5
The width of the tomato patch, w = 381.5 ft.
The relationship between the total area, TA, the area of the vegetable garden, <em>A</em>, and the length of the tomato patch, <em>l</em>, is therefore, given as follows;
A = TA - 381.5·l
338 = TA - 381.5×6.25
TA = 338 + 381.5×6.25 = 2,722.375
Therefore, when l = 6.5, we get
A = 2,722.375 - 381.5×6.5 = 242.625
When l = 7, we get
A = 2,722.375 - 381.5×7 = 51.875
Therefore, we get;