A set of notations (SSS, SAS, ASA and RHS) is used to describe/prove

It is claimed that 55% of marriages in the state of California end in divorce within the first 15 years. A large study was start

kykrilka [37]

Answer:

0.0045 = 0.45% probability that less than two of them ended in a divorce

Step-by-step explanation:

For each marriage, there are only two possible outcomes. Either it ended in divorce, or it did not. The probability of a marriage ending in divorce is independent of any other marriage. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

55% of marriages in the state of California end in divorce within the first 15 years.

This means that $p = 0.55$

Suppose 10 marriages are randomly selected.

This means that $n = 10$

What is the probability that less than two of them ended in a divorce?

This is

$P(X < 2) = P(X = 0) + P(X = 1)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{10,0}.(0.55)^{0}.(0.45)^{10} = 0.0003$

$P(X = 1) = C_{10,1}.(0.55)^{1}.(0.45)^{9} = 0.0042$

$P(X < 2) = P(X = 0) + P(X = 1) = 0.0003 + 0.0042 = 0.0045$

0.0045 = 0.45% probability that less than two of them ended in a divorce

8 0

1 year ago

The heights of the trees for sale at two nurseries are shown below. Heights of trees at Yard Works in feet : 7, 9, 7, 12, 5 Heig

Troyanec [42]

Answer:

The mean of tree heights at Yard Works is 8 feet and at Grow Station is 9 feet.The mean absolute deviation of the tree heights at both yards is 2.

Step-by-step explanation:

1). Height of the trees at Yard Works are = 7,9,7,12,5 feet

So mean height of the trees = (7+9+7+12+5)÷5

= 40÷5 =8 feet

Standard deviation of the trees at Yard works = ∑(║(height of the tree-mean height of the tree))║/(number of trees)

(height of the tree-mean height of the tree)= ║(7-8)║+║(9-8)║+║(7-8)║+║(12-8)║+║(5-8)║ = (1)+1+(1)+4+(3)= 10

Therefore standard deviation = (10)/(5) =2

2). In the same way mean height of the trees at Grow Station=(9+11+6+12+7)/5= 45/5 = 9

Now we will calculate the mean deviation of the tress at Grow Station

= ∑║(height of the tree-mean height of the tree)║/(number of trees)

= ║(9-9)║+║(11-9)║+║(6-9)║+║(12-9)║+║(7-9)║/(5)

= (0+2+3+3+2)/5

= 10/5 =2

Therefore The mean of tree heights at Yard Works is 8 feet and at Grow Station is 9 feet.The mean absolute deviation of the tree heights at both yards is 2.

7 0

2 years ago

Read 2 more answers

Evie and her father are comparing their ages. At the current time, Evie's father is 36 years older than her. Theee years from no

artcher [175]

Let F be the father's current age, and E be Evie's current age.
F = E + 36 this is the current relation between the ages
F + 3 = 5(E + 3) this the relationship in 3 year (hence the + 3)
Then solve by substituting one equation into another:
(E + 36) + 3 = 5(E + 3)
E + 39 =  5E + 15
  24 = 4E
  6 = E
Evie's current age is 6.

7 0

1 year ago

Rory is staying in a cabin on a hill 300 feet above sea level. She walks down the hill to the water’s edge. The equation of her

Anastasy [175]

For this problem, we plug in the numbers for t and the appropriate letters for e to the equation e = 300 - 10t.

a) a = 300 - 10(-2)

simplify: a = 300 + 20

simplify: a = 320 ft.

But, this is not a viable point because when t≤0, she doesn't move anywhere, thus, should consistently be 300 ft.

b) b = 300 - 10(3.5)

simplify: b = 300 - 35

simplify: b = 265 ft.

c) c = 300 - 10(30)

simplify: c = 300 - 300

simplify: c = 0 ft.

8 0

1 year ago

Read 2 more answers

Jason Witten's Salary Negotiation Let's say that tight end Jason Witten (a football player) was given two options when negotiati

Leokris [45]

Answer:

Option 1: It is better for him to be paid per catch, starting with 1 cent and doubling with each catch up to 110

Explanation:

If Jason were to be paid per catch given that he makes a total of 110 catches for the 2017 season in his new contract, he would make a total of :

0.01 × 2^109 = $6.4903711e+30(calculator result, means 6 then 30 digits after)

Therefore it is better for Jason to be paid per catch and not a flat fee of $2000000

3 0

1 year ago