The number of times the spinner landed on a space numbered greater than 4 = 167
Step-by-step explanation:
Step 1 :
Given,
Number of equal area spaces in the spinner = 6
Number of times the spinner was spun = 500
We need to find the number of times the spinner landed on a space numbered greater than 4
Step 2 :
Total number of outcome = 6
Favorable outcomes are = Numbers greater than 4 = 5,6
Total number of favorable outcome = 2
Therefore Probability that the spinner will land on a number that is greater than 4 is 
= 
The number of times that the spinner landed on a space numbered greater than 4 = 500 × = 166.67 = 167 (rounded off to the nearest integer)
Step 3 :
Answer :
The number of times the spinner landed on a space numbered greater than 4 = 167
58 stamps is the number she gets each week. So if she went for one week, 58*1=58. 58*2=116 and so on. Because we don't know the exact number of weeks, we say 58w or 58*w because you multiply however many number of weeks she collects.
Answer: 29
Any number between 28.83 and 29.18 would work
Answer: b) 58%
<u>Step-by-step explanation:</u>
First, let's find the z-score using the formula: 
Next, refer to the z-score table below to find the value of 0.20
Look on the left side for 0.20 and the top for 0.00 to find the percent for 0.20. The table shows the percent above the MEAN so you need to add the percent below the mean (50%) to the value in the table.
0.0793
<u>+ 0.5 </u>
0.5793 = 57.93%
Answer:
i. BC
ii. |AD|=|7-2|=5
Step-by-step explanation:
ABC has the points A(1, 7), B(-2, 2), and C(4, 2).
We use the distance formula to obtain
Using the absolute value method
|BC|=|4--2|=6
The longest side is BC
We use the absolute value method to find the length of AD
|AD|=|7-2|=5
