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Maslowich
2 years ago
5

PLZ HELP 235 people are at RSM summer camp. There are 35 more boys than girls, and 70 fewer adults than girls. How many people o

f each group are at the camp?
Mathematics
1 answer:
Olin [163]2 years ago
4 0

Answer:

number of girls = 90

Number of boys = 125

Number of adults = 20

Step-by-step explanation:

Total people at the summer camp= 235

Let

number of girls=x

Number of boys = x + 35

Number of adults = x - 70

Total people at the summer camp= number of girls + Number of boys + Number of adults

235 = x + (x+35) + (x - 70)

235 = x + x + 35 + x - 70

235 = 3x - 35

Add 35 to both sides

235 + 35 = 3x

270 = 3x

Divide both sides by 3

x= 270/3

= 90

x = 90

number of girls= x = 90

Number of boys = x + 35

= 90 + 35

= 125

Number of adults = x - 70

= 90 - 70

= 20

Total = 90 + 125 + 20

= 235

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Fed [463]
Let L represent the number of cups of lemonade that Marcus sold. Then his revenue can be described by ...
   0.75L + 0.35(L -5) = 7.05
   1.10L -1.75 = 7.05 . . . . . . . . . . eliminate parentheses
   1.10L = 8.80 . . . . . . . . . . . . . . .add 1.75
   L = 8 . . . . . . . . . . . . . . . . . . . . .divide by 1.10

Marcus sold 8 cups of lemonade on Saturday.
7 0
2 years ago
A and B will take the same 10-question examination. Each question will be answered correctly by A with probability .7, independe
MatroZZZ [7]

Answer:

a) The expected number of questions that are answered correctly by both A and B = 11 (7 + 4).

b) The Variance of the number of questions that are answered correctly by either A or B = 2.25.

Step-by-step explanation:

Number of questions in the examination = 10

Probability of A's answer being correct = 0.7

Probability of B's answer being correct = 0.4

The expected number of questions that are answered correctly by both A and B:

           Probability of       Expected        

        Correct Answer       Value          Variance

A              0.7                     7 (0.7 * 10)    2.25

B              0.4                     4 (0.4 * 10)    2.25

Total expected value =    11

           Mean =                  5.5                2.25

5 0
2 years ago
The manufacturer of hardness testing equipment uses steel-ball indenters to penetrate metal that is being tested, however, the m
masha68 [24]

Answer:

1.667-2.31\frac{1.803}{\sqrt{9}}=0.2789  

1.667+2.31\frac{1.803}{\sqrt{9}}=3.055  

So on this case the 95% confidence interval would be given by (0.2789;3.055)  

The 95% confidence interval to judge whether the two indeners result in different measurements is?

Yes the confidence interval not contains the value 0 so we can conclude that the values for Diamond are significantly higher than the values for Steel Ball at 5% of significance.

Step-by-step explanation:

We have the following dataset:

specimen    1     2    3     4      5     6     7    8     9

Steel Ball   51   57   61   70   68   54   65  51   53

Diamond   53   55  63   74   69   56   68  51   56

If we calculate the differences diamond-steel ball we have this datase:

d: 2, -2, 2, 4, 1, 2, 3, 0, 3

The second step is calculate the mean difference  

\bar d= \frac{\sum_{i=1}^n d_i}{n}=1.667

The third step would be calculate the standard deviation for the differences, and we got:

s_d =\frac{\sum_{i=1}^n (d_i -\bar d)^2}{n-1} =1.803

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The confidence interval for the mean is given by the following formula:  

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}} (1)  

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:  

df=n-1=9-1=8  

Since the confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,9)".And we see that t_{\alpha/2}=2.31.

Now we have everything in order to replace into formula (1):  

1.667-2.31\frac{1.803}{\sqrt{9}}=0.2789  

1.667+2.31\frac{1.803}{\sqrt{9}}=3.055  

So on this case the 95% confidence interval would be given by (0.2789;3.055)  

The 95% confidence interval to judge whether the two indeners result in different measurements is?

Yes the confidence interval not contains the value 0 so we can conclude that the values for Diamond are significantly higher than the values for Steel Ball at 5% of significance.

4 0
2 years ago
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Answer:

Step-by-step explanation:

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If she earns $13 an hour lifeguarding, the expression for that is 13L; if she earns $12 an hour car washing, the expression for that is 12W.  The MONEY she earned together by doing both those jobs is

13L + 12W = 124

There you go!

5 0
2 years ago
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Marizza181 [45]

Answer:

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8 0
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