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Paul [167]
2 years ago
5

Jamie, Lily, and Alice collectively weigh 192 pounds. Lily is 3 times as heavy as Jamie, and Alice is 11 pounds. Lighter than Li

ly. How much heavier is Alice than Jamie?
Mathematics
1 answer:
lbvjy [14]2 years ago
5 0

Answer:

Alice is 47 pounds havier than Jamie.

Step-by-step explanation:

Let be "j" the weight in pounds of Jamie, "l" the weight in pounds of Lily and "a" the weight in pounds of Alice.

Based on the data given in the exercise, we can know that:

j+l+a=192       [Equation 1]

l=3j           [Equation 2]

a=l-11          [Equation 3]

Solve "j" from the Equation 2:

j=\frac{l}{3}

Substitute this equatio  and the Equation 3 into the Equation 1 and solve for "l":

\frac{l}{3}+l+(l-11)=192\\\\\frac{7}{3}l=203\\\\l=(203)(\frac{3}{7})\\\\l=87

Substitute the value of "l" into the equation j=\frac{l}{3} to find "j":

j=\frac{87}{3}=29

 Substitute the value of "l" into the Equation 3 to find "a":

a=87-11=76

Subtract the weight of Jamie from the weight of Alice in order to find how much heavier is Alice than Jamie:

76lb-29lb=47lb

Alice is 47 pounds havier than Jamie.

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Elliot collects miniature toy cars. He wants to fill 4 display cases.each display case holds 15 cars. He has 28 cars now, and he
baherus [9]

Answer:

Elliot has to wait 11 months before he has enough cars

Step-by-step explanation:

Elliot has 4 display cases with each case being able to hold 15 cars. Thus we know

total # of cars Elliot can place in his display case = 4 * 15 = 60 cars

From this, we can figure out how many more cars Elliot needs by subtracting the amount of cars he already has

# of cars Elliot needs = 60 - 28 = 32 cars

Now to find the number of months Elliot needs, we divide by how many he can buy each month

# of months Elliot needs to save up for = 32 / 3 = 10 2/3

Assuming Elliot does not get his allowance until the end of the month, we will have to round the number of months up to the nearest integer, 11

7 0
2 years ago
A refund of $3.15 on a $8.64 bill
Varvara68 [4.7K]

8.64 - 3.15 = $5.49 if this is what you are asking

5 0
2 years ago
Read 2 more answers
Which of the following estimates at a 95% confidence level most likely comes from a small sample?
dusya [7]
<span>The <u>correct answer</u> is:

A) 60% ± 18%.

Explanation:

In a confidence interval, the margin of error is given by z*(</span>σ/√n<span>), where </span>σ<span> is the standard deviation and n is the sample size.

First we <u>find the value of z</u>:

We want a 95% confidence level; 95% = 95/100 = 0.95.

To find the z-score, we first subtract this from 1:
1-0.95 = 0.05.

Divide by 2:
0.05/2 = 0.025.

Subtract from 1 again:
1-0.025 = 0.975.

Using a z-table, we find this value in the middle of the table. The z-score that is associated with this value is 1.96.

Back to our formula for margin of error, we have 1.96(</span>σ<span>/</span>√n<span>). The larger n, the sample size, is, the larger its square root is. When we divide by a larger number, our answer is smaller; this gives us a smaller margin of error.

This means that if we had a small sample size, we would divide by a smaller number, making our margin of error larger. The largest margin of error we have in this question is 18%, so this is our correct answer.</span>
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2 years ago
Carys is checking her tax bill for the last year.
mariarad [96]
£18240

since the amount she earned falls within the range of the tax rate 40%, multiply her earnings by 0.4.

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3 0
2 years ago
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Use Part 1 of the Fundamental Theorem of Calculus to find the derivative of the function. g(x) = 7x u2 − 1 u2 + 1 du 6x Hint: 7x
VikaD [51]

It looks like you're given

g(x)=\displaystyle\int_{6x}^{7x}\frac{u^2-1}{u^2+1}\,\mathrm du

Then by the additivity of definite integrals this is the same as

g(x)=\displaystyle\int_0^{7x}\frac{u^2-1}{u^2+1}\,\mathrm du-\int_0^{6x}\frac{u^2-1}{u^2+1}\,\mathrm du

(presumably this is what the hint suggests to use)

Then by the fundamental theorem of calculus, we have

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8 0
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