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1 year ago

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Question 9 (3 points)

1 answer:

Mila [183]1 year ago

5 0

From the dot plot, we have that 90.91% of the students have 5 or more vowels in their first and last names.

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The dot plot states that:

2 students have 4 vowels in their first and last name.
3 students have 5 vowels.
8 students have 6 vowels.
9 students have 7 vowels.

Then:

Total of 2 + 3 + 8 + 9 = 22 students.
3 + 8 + 9 = 20 have or more vowels.

$p = \frac{20}{22} \times 100\% = 90.91\%$

90.91% of the students have 5 or more vowels in their first and last names.

A similar problem is given at brainly.com/question/14354536

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A box contains 5 red and 5 blue marbles. Two marbles are withdrawn randomly. If they are the same color, then you win $1.10; if

topjm [15]

Answer:

a) The expected value is $\frac{-1}{15}$

b) The variance is $\frac{49}{45}$

Step-by-step explanation:

We can assume that both marbles are withdrawn at the same time. We will define the probability as follows

#events of interest/total number of events.

We have 10 marbles in total. The number of different ways in which we can withdrawn 2 marbles out of 10 is $\binom{10}{2}$ .

Consider the case in which we choose two of the same color. That is, out of 5, we pick 2. The different ways of choosing 2 out of 5 is $\binom{5}{2}$ . Since we have 2 colors, we can either choose 2 of them blue or 2 of the red, so the total number of ways of choosing is just the double.

Consider the case in which we choose one of each color. Then, out of 5 we pick 1. So, the total number of ways in which we pick 1 of each color is $\binom{5}{1}\cdot \binom{5}{1}$ . So, we define the following probabilities.

Probability of winning: $\frac{2\binom{5}{2}}{\binom{10}{2}}= \frac{4}{9}$

Probability of losing $\frac{(\binom{5}{1})^2}{\binom{10}{2}}\frac{5}{9}$

Let X be the expected value of the amount you can win. Then,

E(X) = 1.10*probability of winning - 1 probability of losing = $1.10\cdot \frac{4}{9}-\frac{5}{9}=\frac{-1}{15}$

Consider the expected value of the square of the amount you can win, Then

E(X^2) = (1.10^2)*probability of winning + probability of losing = $1.10^2\cdot \frac{4}{9}+\frac{5}{9}=\frac{82}{75}$

We will use the following formula

$Var(X) = E(X^2)-E(X)^2$

Thus

Var(X) = $\frac{82}{75}-(\frac{-1}{15})^2 = \frac{49}{45}$

7 0

2 years ago

At a movie store, Erin pays a monthly fee and is charged for each movie she rents. The table shows the monthly cost when Erin re

Kaylis [27]

It will be $117...i dont really understand how u wrote it but i added all the numbera and got that amount

4 0

1 year ago

A sumo wrestling ring is circular and has a circumference of 4.6\pi \text{ meters}4.6π meters4, point, 6, pi, start text, space,

frez [133]

Answer:

The area of the sumo wrestling ring is $5.29 \pi$

Step-by-step explanation:

The circumference of the circular sumo wrestling ring is $4.6\pi$ , that means its radius $r$ is:

$2\pi r=4.6\pi$

$r=\frac{4.6}{2} =\boxed{2.3\:meters.}$

Now once we have the radius $r$ of the sumo wrestling ring we can find its area $A$ by the following formula:

$A=\pi r^2$

Putting in the value of $r=2.3\:meters$ we get:

$A=\pi (2.3m)^2=\boxed{5.29\pi\:\:m^2}$

Therefore the area of the sumo wrestling ring is ${5.29\pi\:\:m^2$

3 0

1 year ago

Read 2 more answers

When choosing a new school mascot, 80 students voted for an eagle, and 160 students voted for a bulldog. Rounded to the nearest

makvit [3.9K]

Simple.
100% of the student body is 160 + 80, which is 240.

160 is 66.7% of 240.
So 66.7% voted for a bulldog.

Hope this helps!

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2 years ago

Read 2 more answers

Simplify 4a^3b^2 x 3a*6b^5

Strike441 [17]

Answer:

Step-by-step explanation:

(4a³b² )* (3a⁶b⁵) = 4*3 *a⁽³⁺⁶⁾ * b⁽²⁺⁵⁾

= 12a⁹b⁷

4 0

1 year ago