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Stells [14]
1 year ago
8

Round 478.54 to the nearest tenth

Mathematics
2 answers:
Schach [20]1 year ago
8 0
A tenth is the number that occurs after the decimal
If the number after the tenth is five or higher, then you round up
If the number after the tenth if four or lower, then the tenth stays the same value as it is
In this case, the Ume after the tenth is exactly four, so the value of the tenth stays the same
So your answer is 478.5
vaieri [72.5K]1 year ago
7 0
478.5 is the answer
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∠C and ​ ∠D ​ are vertical angles with  m∠C=−x+26 and  m∠D=2x−10 .   What is m∠D ?
Valentin [98]
Vertical angles are made by two intersecting lines .and they are always equal
<span>∠C and ​ ∠D are equal.
so  </span><span>−x+26 =2x-10
-3x=-36
x=36/3
x=12</span>°

∠D= 2x-10
put value of x here
∠D=24-10
∠D=14°
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Frederick designed an experiment in which he spun a spinner 20 times and recorded the results of each spin.He spun a 4 five time
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If the number of trials is changed the number of experimental outcomes also changes
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1 year ago
How does this graph change between point D and point G?
Leona [35]

Answer:

i don't see the graph

Step-by-step explanation:

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2 years ago
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Solve each of the following initial value problems and plot the solutions for several values of y0. Then describe in a few words
Taya2010 [7]

Answer:

Step-by-step explanation:

Answer:

a) y-8 = (y₀-8)  , b) 2y -5 = (2y₀-5)

Explanation:

To solve these equations the method of direct integration is the easiest.

a) the given equation is

          dy / dt = and -8

         dy / y-8 = dt

We change variables

          y-8 = u

         dy = du

We replace and integrate

           ∫ du / u = ∫ dt

           Ln (y-8) = t

We evaluate at the lower limits t = 0 for y = y₀

          ln (y-8) - ln (y₀-8) = t-0

Let's simplify the equation

           ln (y-8 / y₀-8) = t

           y-8 / y₀-8 =

            y-8 = (y₀-8)

b) the equation is

            dy / dt = 2y -5

            u = 2y -5

            du = 2 dy

            du / 2u = dt

We integrate

             ½ Ln (2y-5) = t

We evaluate at the limits

            ½ [ln (2y-5) - ln (2y₀-5)] = t

            Ln (2y-5 / 2y₀-5) = 2t

            2y -5 = (2y₀-5)

c) the equation is very similar to the previous one

             u = 2y -10

             du = 2 dy

             ∫ du / 2u = dt

             ln (2y-10) = 2t

We evaluate

             ln (2y-10) –ln (2y₀-10) = 2t

               2y-10 = (2y₀-10)

4 0
1 year ago
Josh and his friends bought vanilla wafers for $4 per packet and chocolate wafers for $1 per packet at a carnival. they spent a
KIM [24]
45 = 4X + 1X

45= 4×(9) +1×(9)

45= 36 + 9

45 = 45

OR
45= 4X + 1X

45 = 4(9) + 1(9)

45 = 36 + 9
-36= -36
9 = 9
-9 = -9
0=0

You have to evaluate the problem this way in order to figure out the number of wafers in all. Either way the answer is still 9. I replaced the variable x with 9 in order to get my answer
6 0
1 year ago
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