Answer:
There is a 38.97% probability that this student earned an A on the midterm.
Step-by-step explanation:
The first step is that we have to find the percentage of students who got an A on the final exam.
Suppose 13% students earned an A on the midterm. Of those students who earned an A on the midterm, 47% received an A on the final, and 11% of the students who earned lower than an A on the midterm received an A on the final.
This means that
Of the 13% of students who earned an A on the midterm, 47% received an A on the final. Also, of the 87% who did not earn an A on the midterm, 11% received an A on the final.
So, the percentage of students who got an A on the final exam is

To find the probability that this student earned an A on the final test also earned on the midterm, we divide the percentage of students who got an A on both tests by the percentage of students who got an A on the final test.
The percentage of students who got an A on both tests is:

The probability that the student also earned an A on the midterm is

There is a 38.97% probability that this student earned an A on the midterm.
Answer:
<u>2</u><u>2</u><u>1</u><u> </u><u>g</u>
The up pinned pic is of inverse variation typed answer.. If u want word problem type answer here are the steps (EVEN IF THE STEPS ARE DIFFERENT ANSWERS REMAIN SAME)
Step-by-step explanation:
Mass of wire from 22cm = 374g
Mass of wire from 1 cm = 374÷22 = 17g
Mass of wire from 13 cm = 13×17 = <u>2</u><u>2</u><u>1</u><u> </u><u>g</u>
Answer: cos(53o)=y/5
<span>T
riangle abc is a right triangle and sin(53o) = . solve for x and round to the nearest whole number. which equation correctly uses the value of x to represent the cosine of angle a?cos(53o) = 4/xcos(53o) = y/5cos(53o) = x/4cos(53o) = 5/y</span>
Answer:
A) The mean of the chi-square distribution is 0
A) is not a property of chi square distribution.
Step-by-step explanation:
We have to find the properties of a chi square test.
A) False
The mean of a chi square distribution is equal to the degree of freedom.
B) True
The chi-square distribution is non symmetric.
C) True
The chi square value can be zero and positive.
It can never be negative because it is based on a sum of squared differences .
D) True
The chi-square distribution is different for each number of degrees of freedom.
When we are working with a single population variance, the degree of freedom is n - 1.