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Stells [14]
2 years ago
8

Round 478.54 to the nearest tenth

Mathematics
2 answers:
Schach [20]2 years ago
8 0
A tenth is the number that occurs after the decimal
If the number after the tenth is five or higher, then you round up
If the number after the tenth if four or lower, then the tenth stays the same value as it is
In this case, the Ume after the tenth is exactly four, so the value of the tenth stays the same
So your answer is 478.5
vaieri [72.5K]2 years ago
7 0
478.5 is the answer
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W = 3x + 7y solve for y
mario62 [17]

Answer:

The value of the equation y=\frac{W-3x}{7}.

Step-by-step explanation:

Consider the provided equation.

W = 3x + 7y

We need to solve the provided equation for y.

Subtract 3x from both side.

W-3x= 3x-3x+ 7y

W-3x=7y

Divide both sides by 7.

\frac{7y}{7}=\frac{W-3x}{7}

y=\frac{W-3x}{7}

Hence, the value of the equation is y=\frac{W-3x}{7}.

8 0
2 years ago
baker has 5\dfrac145 4 1 ​ 5, start fraction, 1, divided by, 4, end fraction pies in her shop. She cut the pies in pieces that a
kupik [55]

Answer:

The answer is "She cut a total of 42 pieces of pie".

Step-by-step explanation:

Given :

Total pie=  5 \frac{1}{4}

cut pie = \frac{1}{8}

The number of pieces of the pie she has=?

Solve the mixed fraction value:

\to 5 \frac{1}{4}= \frac{21}{4}

If she cuts the pieces into the entire pie, that is  = \frac{1}{8}  

So, the equation is:

\to \frac{21}{4} = \frac{1}{8} \times x

\to x= \frac{21 \times 8}{4}\\\\ \to x= 21 \times 2\\\\ \to  x=42

7 0
2 years ago
How much heat is required to raise the temperature of
Elina [12.6K]

Answer:

The amount of heat required to raise the temperature of liquid water is 9605 kilo joule .

Step-by-step explanation:

Given as :

The mass of liquid water = 50 g

The initial temperature = T_1 = 15°c

The final temperature = T_2  = 100°c

The latent heat of vaporization of water = 2260.0 J/g

Let The amount of heat required to raise temperature = Q Joule

Now, From method

Heat = mass × latent heat × change in temperature

Or, Q = m × s × ΔT

or, Q =  m × s × ( T_2 - T_1 )

So, Q = 50 g × 2260.0 J/g × ( 100°c - 15°c )

Or, Q =  50 g × 2260.0 J/g × 85°c

∴   Q = 9,605,000  joule

Or, Q =  9,605 × 10³ joule

Or, Q = 9605 kilo joule

Hence The amount of heat required to raise the temperature of liquid water is 9605 kilo joule . Answer

4 0
2 years ago
Your drawer has 5 pairs of black socks, 4 pairs of gray socks, 2 pairs of white socks, 1 pair of brown socks, and 1 pair of blue
Sergeeva-Olga [200]
5 pairs of black socks*2 because it’s a pair= 10 socks
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2 pairs of white socks*2=4
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7 0
2 years ago
∠A and ∠B are complementary angles of right triangle ABC, cos A = 0.83, and cos B = 0.55. What is sin A + sin B?
sergiy2304 [10]
As the angles are complementary sin A = cos B and  sin B = cos A

so sin A + sin B =  0.55 + 0.83 =  1.38
4 0
2 years ago
Read 2 more answers
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