Answer:
a) Null hypothesis:
Alternative hypothesis:
b) 
(1)
Replacing we got:
The p value for this case would be given by:
c) For this case we see that the p value is higher than the significance level of 0.05 so then we have enough evidence to FAIL to reject the null hypothesis and we can't conclude that the true proportion workers belonged to unions is significantly higher than 11.3%
Step-by-step explanation:
Information given
n=400 represent the random sample taken
X=52 represent the workers belonged to unions
estimated proportion of workers belonged to unions
is the value that we want to test
represent the significance level
Confidence=95% or 0.95
z would represent the statistic
represent the p value
Part a
We want to test if the true proportion of interest is higher than 0.113 so then the system of hypothesis are.:
Null hypothesis:
Alternative hypothesis:
Part b
The statistic is given by:
(1)
Replacing we got:
The p value for this case would be given by:
Part c
For this case we see that the p value is higher than the significance level of 0.05 so then we have enough evidence to FAIL to reject the null hypothesis and we can't conclude that the true proportion workers belonged to unions is significantly higher than 11.3%
Answer:
Option 1
Step-by-step explanation:
The given equation equals 3072, so find the other equation that equals 3072.
Option 1 = 3072 - correct
Option 2 = 432 - wrong
Option 3 = 2883 - wrong
Option 4 = 432 - wrong
I hope this helps!
Let X be the number of female employee. Let n be the sample size, p be the probability that selected employee is female.
It is given that 45% employee are female it mean p=0.45
Sample size n=60
From given information X follows Binomial distribution with n=50 and p=0.45
For large value of n the Binomial distribution approximates to Normal distribution.
Let p be the proportion of female employee in the given sample.
Then distribution of proportion P is normal with parameters
mean =p and standard deviation = 
Here we have p=0.45
So mean = p = 0.45 and
standard deviation = 
standard deviation = 0.0642
Now probability that sample proportions of female lies between 0.40 and 0.55 is
P(0.40 < P < 0.45) = 
= P(-0.7788 < Z < 1.5576)
= P(Z < 1.5576) - P(Z < -0.7788)
= P(Z < 1.56) - P(Z < -0.78)
= 0.9406 - 0.2177
= 0.7229
The probability that the sample proportion of females is between 0.40 and 0.55 is 0.7229
Answer:
Rs. X + Rs. 10y
Step-by-step explanation:
Charge for 40 km travel = Rs. x per km
Charge for every additional km traveled = Rs. y
Amount paid for 50 km
Fixed charge for 40km = Rs. X
Additional km = 50 - 40 = 10 kilometer
Total charge :
Rs. X + Rs. 10y
