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2 years ago

What are the roots of f(x) = x2 – 48?

Mathematics

2 answers:

notsponge [240]2 years ago

7 0

Answer:

(x +sqrt(48)) (x-sqrt(48))

Step-by-step explanation:

sqrt = Square Root

sqrt(48) = 6.928

lana66690 [7]2 years ago

6 0

Answer:

If you mean x-intercepts and your equation is x^2 -48 then the roots are +6.928 and -6.928

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Answer:

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Step-by-step explanation:

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B: As NM = x therefore it can not be equal to $x\sqrt{2\\}$ .

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Therefore, $tan (45) = 1$ and not equal to $\frac{\sqrt{2} }{2}$

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