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Evgesh-ka [11]
2 years ago
7

Suppose y varies directly with x. If y = –4 when x = 8, what is the equation of direct variation? Complete the steps to write th

e equation of direct variation. Start with the equation of direct variation y = kx. Substitute in the given values for x and y to get . Solve for k to get . Write the direct variation equation with the value found for k. The equation is
Mathematics
2 answers:
avanturin [10]2 years ago
8 0

Answer:

1. Start with the equation of direct variation y = kx.

2.Substitute in the given values for x and y to get: -4=k(8)

3. Solve for k to get: -1/2

4. Write the direct variation equation with the value found for k. The equation is: y=(-1/2)x

Step-by-step explanation:

I just did it on e2020

Sauron [17]2 years ago
6 0

Answer:

y = -1/2 x

Step-by-step explanation:

Follow the directions "Complete the steps to write the equation of direct variation. Start with the equation of direct variation y = kx. Substitute in the given values for x and y to get . Solve for k to get . Write the direct variation equation with the value found for k."

y = kx substitute y = -4 and x = 8.

-4 = k*8

-4/8 = k

-1/2 = k

So the equation is y = -1/2(x).

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The 99 percent confidence interval for the average weight of a product is from 71.36 lbs. to 78.64 lbs. Can we conclude that μ i
Ilya [14]

Answer:

Step-by-step explanation:

Hello!

To decide over a hypothesis test using a confidence interval the following conditions are to be met:

1. The hypotheses should be two-tailed.

2. The hypotheses and the confidence interval should be made for the same parameter.

3. The confidence level and the significance level should be complementary, so if the CI is 1-α: 0.99 the level of significance should be α: 0.01

If all conditions are met, the decision rule is the following:

If the value stated in the null hypothesis is contained by the CI, the decision is to not reject the null hypothesis.

If the value stated in the null hypothesis is not contained by the CI, the decision is to reject the null hypothesis.

Let's say in this example the hypotheses are:

H₀: μ = 71

H₁: μ ≠ 71

α: 0.01

99% Confidence level is (71.36;78.64).

As you can see, 71 is not contained in the CI so the decision to take is to reject the null hypothesis, in other words, the population mean is not 71.

I hope it helps!

6 0
2 years ago
11. A basketball team of 16 players consists of 6 guards, 7 forwards, and 3 centers. The coach decides to randomly select 5 play
Citrus2011 [14]

Answer:

0.2163

Step-by-step explanation:

Firstly, we need to evaluate the total number of possible outcomes. Since there are 16 players, and we are selecting just 5, the total number of possibilities is 16C5= 4,368

Now, we know we need 2 guards from 6 , 2 forwards from 7 and 1 center from 3 to start the game. Since we are selecting, it is a combination problem. These can be done in the following number of ways:

6C2 * 7C2* 3C1

The probability is thus (6C2 * 7C2* 3C1 )/16C5 = 945/4368 = 0.2163

8 0
2 years ago
PLEASE HELP TO SOLVE QUESTION with full process c) Mr. Thapa bought a motorbike for Rs 1,25,000 and fixed its price 20 % above t
klasskru [66]

Answer: Rs. 1,52,550

Step-by-step explanation:

CP of motorcycle = 125000

Selling Price fixed = 125000 + 20% = 150000

10% discount = 150000*10% = 15000

SP after 10% discount

= 150000-15000= 135000

VAT at 13% = 135000 * .13 = 17550

Mr Gurung paid total

135000 + 17550 = 152550

8 0
2 years ago
Read 2 more answers
The number of calls coming per minute into a hotel reservation center is Poisson random variable with mean 3.
natima [27]

Answer:

a) 0.05

b) 0.9826

c) 0.000039308

Step-by-step explanation:

a) P_X(0) = \frac{e^{-3}3^0}{0!} = e^{-3} =  0.05

b) For two minutes, the mean is doubled, hence it is 6. In order to calculate the probability of al least two calls arriving, we calculate first the probability of the complementary event: At most 1 call will arrive. For that probability, we need to sum the probabilities of 0 and 1.

P_X(0) = e^{-6}

P_X(1) = \frac{e^{-6}*6^1}{1!} = 6*e^{-6}

Hence,

P(X \geq 2) = 1-P(X < 2) = 1- 7*e^{-6} = 0.9826

c) For five minutes the mean is 15. We need to sum the probabilities of 0, 1 and 2.

P_X(0) = e^{-15}

P_X(1) = e^{15}*15

P_X(2) = \frac{e^{-15}*15^2}{2!} = 112.5*e^{-15}

As a result,

P(X \leq 2) = e^{-15}(1+15+112.5) = 0.000039308

Practically 0

4 0
2 years ago
determine 4th term in the geometric sequence whose first term is -2 and whose common ratio is -5. does anyone know what this can
9966 [12]
The terms in a geometric sequence are given by: A = ar^(n-1)
where A is the nth term in the sequence.
a = first term in the sequence (-2)
r = common ratio (-5)
n = number of the term (4)

A = (-2)(-5)^(4-1)
A = (-2)(-5)^(3)
A = (-2)(-125)
A = 250

4 0
2 years ago
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