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Vinvika [58]
2 years ago
11

11. A basketball team of 16 players consists of 6 guards, 7 forwards, and 3 centers. The coach decides to randomly select 5 play

ers to start the game. What is the probability of 2 guards,
2 forwards, and 1 center starting the game?
Mathematics
1 answer:
Citrus2011 [14]2 years ago
8 0

Answer:

0.2163

Step-by-step explanation:

Firstly, we need to evaluate the total number of possible outcomes. Since there are 16 players, and we are selecting just 5, the total number of possibilities is 16C5= 4,368

Now, we know we need 2 guards from 6 , 2 forwards from 7 and 1 center from 3 to start the game. Since we are selecting, it is a combination problem. These can be done in the following number of ways:

6C2 * 7C2* 3C1

The probability is thus (6C2 * 7C2* 3C1 )/16C5 = 945/4368 = 0.2163

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Candace leaves her house and starts jogging at a pace of 480 feet per minute. Five minutes later, her brother runs after her at
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Answer:

The answer to your question is time = 20 min

Step-by-step explanation:

Data

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Brother = 660 ft/min

Process

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    distance = speed xtime

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3.- Solve by equality

                  2400 + 480t = 600t

                  2400 = 600t - 480t

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4.- I will solve the equation given

                   480t = 660(t - 112112)

                   480t - 660t = -112112

                            -120t = -112112

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It is rigid because all side lengths and angles are congruent.

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Answer:

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∠CAB =∠MRQ = 29°

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1. BC ≅ MQ       (Additional information)

2. AC ≅ RQ       (Additional information)

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