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Ber [7]
2 years ago
11

Find the 17th term of the of the arithmetic sequence-5,0,5,10

Mathematics
2 answers:
Lilit [14]2 years ago
8 0
An=a1+d(n-1)
first term is -5 (only way for it to make sense)
common difference is proabtly 5

an=-5+5(n-1)
17th term
an=-5+5(17-1)
an=-5+5(16)
an=-5+80
an=75
17th term is 75
kifflom [539]2 years ago
4 0
The n-th term for an arithmetic sequence with a common difference of 5 and a first term of -5 is given by
  a(n) = -5 + 5(n-1)
or
  a(n) = 5n -10

The 17th term is found by evaluating this for n=17.
  a17 = 5·17 - 10
  a17 = 75
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Here we are given with a triangle with smaller triangles formed due to the altitude on AC. Given:

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We have to find the value for sin \theta

So, Let's start solving....

In ∆ADB and ∆ABC,

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So, ∆ADB ~ ∆ABC (By AA similarity)

The corresponding sides will be:

\sf{ \dfrac{AD}{AB}  =  \dfrac{AB}{AC} }

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AC = 10

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\sf{ \dfrac{AD}{6}  =  \dfrac{6}{10} }

\sf{AD =  \dfrac{6 \times 6}{10}  = 3.6}

In ∆ADB, we have to find sin \theta which is given by perpendicular/base:

\sf{\sin( \theta)  =  \dfrac{AD}{AB} }

Plugging the values of AD and AB,

\sf{\sin( \theta)  =  \dfrac{3.6}{6} }

Simplifying,

\sf{ \sin( \theta)  =  \dfrac{3}{5}  =  \boxed{ \red{0.6}}}

And this is our final answer.....

Carry On Learning !

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