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Lina20 [59]
2 years ago
10

Gordon​ Miller's job shop has four work​ areas, A,​ B, C, and D. Distances in feet between centers of the work areas​ are: A B C

D A − 5 9 7 B − − 6 8 C − − − 11 D − − − − Workpieces moved per week between work areas​ are: A B C D A − 900 900 500 B − − 500 200 C − − − 600 D − − − − It costs Gordon ​$22 to move 1 work piece 1 foot.What is the weekly total material handling cost of the layout?

Mathematics
1 answer:
andreev551 [17]2 years ago
4 0

Answer: $600,600

Step-by-step explanation:

Total handling cost :

Workpiece moved * cost * distance

Work area A :

-, (5 × 22 × 900), (9 × 22 × 900), (7 × 22 × 500)

-, 99000, 178200, 77000

Work area B:

-, -, (6 × 22 × 500), (8 × 22 × 200)

-, -, 66000, 35200

Work area C:

-, -, -, (11 × 22 × 600)

-,-,-, 145200

Work area D:

-, -, -, -

Total weekly handling cost :

(99000 + 178200 + 77000 + 66000 + 35200 + 145200)

= $600,600

Kindly check attached picture for more explanation

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rosijanka [135]
$200. in the math so duh
7 0
2 years ago
4(5x−3)+5x+5 = 118<br><br> solve for x
EleoNora [17]

Answer:

x=1+2/15

Step-by-step explanation:

4(5x-3)=5x+5=118

We move all terms to the left:

4(5x-3)-(5x+5)=0

We multiply parentheses

20x-(5x+5)-12=0

We get rid of parentheses

20x-5x-5-12=0

We add all the numbers together, and all the variables

15x-17=0

We move all terms containing x to the left, all other terms to the right

15x=17

x=17/15

x=1+2/15

   

   

8 0
1 year ago
A government official is in charge of allocating social programs throughout the city of Vancouver. He will decide where these so
otez555 [7]

Answer: (0.132132, 0.274368)

Step-by-step explanation:

Given : A simple random sample of 123 people living in Gastown and finds that 25 have an annual income that is below the poverty line.

i.e. n= 123

\hat{p}=\dfrac{25}{123}\approx0.203252

Critical value for 95% confidence interval : z_{\alpha/2}=1.96

Confidence interval for population :

\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

i.e. 0.203252\pm (1.96)\sqrt{\dfrac{0.203252(1-0.203252)}{123}}

0.203252\pm (1.96)\sqrt{\dfrac{0.203252(1-0.203252)}{123}}\\\\\0.203252\pm0.071118\\\\=(0.20325-0.071118,\ 0.203252+0.071118)\\\\=(0.132132,\ 0.274368)

Hence, the 95% confidence interval for the true proportion of Gastown residents living below the poverty line : (0.132132, 0.274368)

5 0
2 years ago
You are a pharmacy technician. You need to prepare a 0.85-gram dose of a liquid antibiotic. The medicine is concentrated at 250
Xelga [282]

Answer:

17mL

Step-by-step explanation:

Convert 0.85 gr to miligrams

If 100 mg is 1 gr. Then, 0.85 gr is 850 mg

So, 850 multiply for 5ml and divide for 250 ml

or 850mg  \frac{5ml}{250mg}

So all mg is gone and the amount of mililiters is 17

5 0
2 years ago
Read 2 more answers
What is 2 (log Subscript 3 Baseline 8 + log Subscript 3 Baseline z) minus log Subscript 3 Baseline (3 Superscript 4 Baseline min
Ilya [14]

Answer:

Value of expression in single logarithm is \log_3\left(2z^2\right).

Step-by-step explanation:

Given expression is,

2\left(\log_3\left(8\right)+\log_3\left(z\right)\right)-\log_3\left(3^4-7^2\right)

Now using logarithmic rule to solve the expression as follows,

Applying product rule of logarithmic,

\log_c\left(a\right)+\log_c\left(b\right)=\log_c\left(ab\right)

Therefore,

2\log_3\left(8z\right)-\log_3\left(3^4-7^2\right)

Applying power rule of logarithmic,

a\log_c\left(b\right)=\log_c\left(b^a\right)

Therefore,

\log_3\left(\left(8z\right)^2\right)-\log_3\left(3^4-7^2\right)

\log_3\left(\left(64z^2\right)\right)-\log_3\left(3^4-7^2\right)

Applying quotient rule of logarithmic,

\log_c\left(a\right)-\log_c\left(b\right)=\log_c\left(\frac{a}{b}\right)

Therefore,

\log_3\left(\dfrac{\left(64z^2\right)^2}{3^4-7^2}\right)

Simplifying,

\log_3\left(\dfrac{\left(64z^2\right)^2}{81-49}\right)

\log_3\left(\dfrac{\left(64z^2\right)^2}{32}\right)

\log_3\left(2z^2\right)

Therefore value of expression is \log_3\left(2z^2\right)

6 0
2 years ago
Read 2 more answers
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